anonymous
  • anonymous
PLEASE HELP FOR MEDAL AND FAN
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
this is confusing? sorry i really don't know...
anonymous
  • anonymous
i have no clue what to do

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anonymous
  • anonymous
Do you understand absolute values?
anonymous
  • anonymous
@jaeuni noo:(
anonymous
  • anonymous
you notice how you have a "bar" on each side of the x-4?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
When you have bars like that, you know that it takes the absolute value of whatever happens inside - whether the number inside becomes a negative or positive (after you plug in a value for x) you will always take the absolute value (positive) of that number. Think of an absolute value as the distance of some number on a number line, away from zero - disregarding it's direction (it will never be positive, since "distance w/o direction" can only be a positive number...get it?
anonymous
  • anonymous
kind of yeah...
anonymous
  • anonymous
|dw:1446614201243:dw|
anonymous
  • anonymous
Does that picture make better sense?
anonymous
  • anonymous
oh yeah it does actuslly!:)
anonymous
  • anonymous
So what would the answer of this sample problem be?|dw:1446614420677:dw|
anonymous
  • anonymous
would it first be negative three minus seven???
anonymous
  • anonymous
right
anonymous
  • anonymous
and that is?
anonymous
  • anonymous
sorry idk what it did there... i got -10, so ten?
anonymous
  • anonymous
No, that's perfect....because despite -3-7 = -10, since you're taking the absolute value, it would just be ten
anonymous
  • anonymous
hmm ok whats next
anonymous
  • anonymous
Now that we understand absolute values, we can approach your problem. First solve it like a regular equation when you try to get x alone
anonymous
  • anonymous
so id plus 4 on both sides?
anonymous
  • anonymous
yep, and what would x be less than?
anonymous
  • anonymous
16?
anonymous
  • anonymous
Right, so you know that the absolute value of x needs to be less than 16...knowing that should be able to help you know which 2 solution sets you can cross off
anonymous
  • anonymous
A and C?
anonymous
  • anonymous
Right because both A and C have solution sets that include (16, positive infinity)
anonymous
  • anonymous
Now, can x ever be 16?
anonymous
  • anonymous
no
anonymous
  • anonymous
does that mean its D?
anonymous
  • anonymous
Do you know the difference between |dw:1446615022999:dw| brackets vs. parenthesis when it comes to solution sets?
anonymous
  • anonymous
no
anonymous
  • anonymous
|dw:1446615144552:dw| The top one is a bracket and the bottom one is a parenthesis You draw brackets when your x and y value can be included as one of the solutions and you draw a parenthesis when your x and y values can not be included as one of the solutions
anonymous
  • anonymous
oh and so its the one in parantheses then?
anonymous
  • anonymous
Yep
anonymous
  • anonymous
wow thanks man!:)
anonymous
  • anonymous
np ^^

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