anonymous
  • anonymous
When power cables are suspended between two towers they form a curve called the catenary shown below. The equation of the curve is given by: y=acosh(x/a) where the distance between the two towers is 2b. Find the slope of the catenary where the cable meets the right hand tower.
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1446677899008:dw|
anonymous
  • anonymous
that is the drawing that it gives me
anonymous
  • anonymous
I am not sure how to start it

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inkyvoyd
  • inkyvoyd
d/dx sinh(x)=cosh(x) d/dx cosh(x)=-sinh(x) to derive these formulas use the equivalent cosh(x)=(e^x+e^-x)/2 and sinh(x)=(e^x-e^-x)/2
anonymous
  • anonymous
\[y=a(\frac{ e^(x/a)+e^(-x/a) }{ 2 })\]
anonymous
  • anonymous
the (x/a)'s are exponents
anonymous
  • anonymous
does x=b? since I am trying to find the slope of the right side
inkyvoyd
  • inkyvoyd
yeah prolly
inkyvoyd
  • inkyvoyd
but there's no need to use the expanded form. just do d/dx cosh(x)=-sinh(x)

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