Ac3
  • Ac3
The cable of the 1700 kg elevator cab shown the figure snaps when the cab is at rest at the first floor, where the cab bottom is a distance d = 4.6 m above a spring of spring constant k = 0.12 MN/m. A safety device clamps the cab against guide rails so that a constant frictional force of 4.6 kN opposes the cab's motion. (Assume that the frictional force on the cab is negligible when the cab is stationary.) A) Find the speed of the cab right before it hits the spring B)Find the maximum distance x that the spring is compressed (frictional force still acts during compression)
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Ac3
  • Ac3
C) Find the total distance the cab will bounce back up the shaft D)Using conservation of energy, find the approximate total distance the cab will move before coming to rest.
Ac3
  • Ac3
@freckles
Ac3
  • Ac3
@IrishBoy123

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Ac3
  • Ac3
I'm having a hard time guys I got part A it's 8.08m/s
Ac3
  • Ac3
1 Attachment
Ac3
  • Ac3
I found B. x=1.07m
Ac3
  • Ac3
I got C. It goes up 3.23m
Ac3
  • Ac3
I just found the solution to this problem only with different numbers, but I don't understand what they're doing for the last part. I'll post so you can see maybe you'll be able to understand.
Ac3
  • Ac3
http://www.slader.com/textbook/9781118230718-fundamentals-of-physics-10th-edition/207/problems/63/
Ac3
  • Ac3
Want me to post how I got those answers?
freckles
  • freckles
ok I think I found some formulas... and I'm guessing g=9.8 something is a given like some kind of kinetic energy thingy
Ac3
  • Ac3
we're supposed to know g so yes
Ac3
  • Ac3
I'm trying something right now It's gonna take forever but I think I'll be able to find the total distance
freckles
  • freckles
Going to copy and paste your problem here so I don't have to scroll up when typing this: The cable of the 1700 kg elevator cab shown the figure snaps when the cab is at rest at the first floor, where the cab bottom is a distance d = 4.6 m above a spring of spring constant k = 0.12 MN/m. A safety device clamps the cab against guide rails so that a constant frictional force of 4.6 kN opposes the cab's motion. (Assume that the frictional force on the cab is negligible when the cab is stationary.) \[m=1700 kg \\ d=4.6 m \\ k=0.12 \cdot 10^{6} \frac{N}{m} \\F_f=4.6 \cdot 10^{3} N \\ d_{eq}=\frac{ m \cdot g}{k}=\frac{1700 \cdot 9.8}{0.12 \cdot 10^{6}}=0.1388 \overline{3} \text{ or } \frac{833}{6000} \approx 0.1388 \\ \\ d_{eq} \text{ is the distance the spring is compressed when the cab comes to rest } \] \[m \cdot g \cdot (d+d_{eq})=F_f \cdot D_{total } \] should plug in the numbers and solve for distance total which is D_(total)
Ac3
  • Ac3
I just finished the really long way I told you about and got 16.7 which is correct when you plug in all the numbers for yours do you get the same? I'm curious
Ac3
  • Ac3
I got 17 but it asks for an approximation so that is right. Mine is exact lol took about 20min.
freckles
  • freckles
that means something is off about that one formula and that this other formula I have is right because the first one I got 17.something and this other one I got 16.9
Ac3
  • Ac3
what's the formula that gave you 16.9?
freckles
  • freckles
\[m \cdot g (d_{eq}+d)=\frac{1}{2} k \cdot d_{eq}^2+F_f \cdot D_{total }\]
freckles
  • freckles
for some reason this one site as the 1/2*k*d_eq^2 thingy while this one doesn't
freckles
  • freckles
but there is another mistake in this one site
freckles
  • freckles
http://www.myfavoritetutor.net/conservation-of-energy-1/ http://www.dhouts.com/unit_2_slns.pdf
freckles
  • freckles
I thought the explanation on that first site was better but I think that there is mistakes on the first site
freckles
  • freckles
https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=2&cad=rja&uact=8&ved=0CCQQFjABahUKEwibsv_MxPjIAhWDSiYKHVF4D9Q&url=http%3A%2F%2Fwww.dhouts.com%2Funit_2_slns.pdf&usg=AFQjCNEdFoFK3PmjBS0mr5F87u2habJQVA just in case second one doesn't work
freckles
  • freckles
for example on that first site they said k=.15*10^(-6) N/m instead of .15*10^6 N/m
Ac3
  • Ac3
The 2nd one works. Now how did you know Deq was mg/k??
Ac3
  • Ac3
That's an equation I wasn't given in class is why I ask.
freckles
  • freckles
that is what the first site explains does spring force+frictional force-gravitational force=0 mean anything to you?
freckles
  • freckles
that Deq=mg/k is what we get if we assume the frictional force is 0
freckles
  • freckles
which is when the cab is going nowhere
Ac3
  • Ac3
Sounds like a modification of the formulas I know. Usually we say -frictional force
Ac3
  • Ac3
That makes perfect sense
freckles
  • freckles
well in all honesty I know nothing about physics I just look up formulas and plug in numbers :p I guess some of it makes sense though
Ac3
  • Ac3
LMFAO
Ac3
  • Ac3
Dude your pretty smart if your figuring out physics problems and haven't been taught physics.
Ac3
  • Ac3
You have to be really good at math I'm impressed freckles you have a degree?
freckles
  • freckles
I do have a math degree with no physics background whatsoever. If I can find a formula, I think I can help you... I might not be so good on the explanation part of it though .
Ac3
  • Ac3
That explains it, physics is just applied math and you seem to be able to understand the formulas really well. I can't wait till i'm at your level of intellect freckles Thanks for your help man I appreciate it.
Ac3
  • Ac3
How do i give you a medal?
freckles
  • freckles
lol... You don't have to but normally there is a best response button.
Ac3
  • Ac3
Oh that's it? just gave you one.
freckles
  • freckles
I will give you one for all your hard work and effort you had put into before I got here. And also I'm really not that smart. Getting a degree just made me feel how dumb I really am. :p Like there is so much math and I do not know it all.
freckles
  • freckles
best response=medal
Ac3
  • Ac3
good to know and i agree hopefully by the time i'm 45 i'll be well rounded in every subject i want to be near expert level in the math and sciences
freckles
  • freckles
I have already accepted I will never be good in the language/english studies
freckles
  • freckles
Maybe okay... but not great.
Ac3
  • Ac3
lol same here
freckles
  • freckles
Don't get to 45 too fast! Goodnight.
Ac3
  • Ac3
night man thanks again and i'm not gonna close this question because i want to come back to it later.
freckles
  • freckles
also I'm not a man
freckles
  • freckles
but I know what you mean man :p
Ac3
  • Ac3
I love meeting women that are smarter than i am
freckles
  • freckles
lol
Ac3
  • Ac3
have a good evening now rest well
freckles
  • freckles
I don't know if I'm smarter than you.
freckles
  • freckles
you too

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