shelby1290
  • shelby1290
Factor 625-(k-5)^2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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baru
  • baru
clue: \(625=25^2\)
baru
  • baru
\(a^2-b^2=(a+b)(a-b)\)
shelby1290
  • shelby1290
√625 = 25 √25k^2=5k (25+5k)(25-5k) @baru like that?

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baru
  • baru
\(625-(k-5)^2\\25^2-(k-5)^2\\now ~use ~the~formula~ i~gave\\(25+k-5)(25-k+5)\\(20+k)(30-k)\)
shelby1290
  • shelby1290
how did 625 turn into 25?
baru
  • baru
625 turned into \(25^2\)
baru
  • baru
because \(25 \times 25 =625\)
baru
  • baru
which step exactly is confusing you?
baru
  • baru
@shelby1290
shelby1290
  • shelby1290
oh i was thinking that you got 25 from doing 625 divided by 25 and then somehow you carried over the power of 2
baru
  • baru
i just re-wrote 625 as \(25^2\) so that i can use the formula \(a^2-b^2=(a+b)(a-b)\) i substituted a=25 b=k-5
shelby1290
  • shelby1290
ahhhhh okay i see!

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