• anonymous
Indefinite Integral Calculation: S=integral S(X^2+4x)/(x^3+6x^2+5)dx So I get that I have to do the u substitution: u = x^3 + 6x^2 +5 --> du = 3x^2 +12x --> 1/3du = x^2 +4x dx then --> 1/3 S 1/u du --> 1/3ln(u) --> then i plug u back in. The problem I am having is the symbolab calculator that I'm using to check my work is adding this extra step that I don't understand. it gets u = x^3 +6x^2 +5 then it gets du = 3x(x+4) then dx = 1/3x(x+4) du it plugs it in as: S (x^2+4x)/u (times) 1/(3x(x+4)du then 1/3u du, after which it lines up with what I got. help pl0x :)
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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