A 50.0 kg sled is placed on ice where μs=0.12 and μk=0.08. A child attaches a rope to the sled and slowly increases the tension in the rope. Calculate the force of friction acting on the sled when the tension is the following values:
b. 50 N
c. 75 N
d. 100 N
Stacey Warren - Expert brainly.com
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friction force = \(weight \times \mu\)
so i would multiply 12 and 0.12
where did 12 come from?
weight of the sled? how much is that? in Newtons
accurate to 9 decimal places?wow!! how did you get that??
calculate friction force using \(\mu_s\) first and then with\(\mu _k\)
if tension applied is greater than friction force calculated with \(\mu_s\) then, firction force = (weight \(\times \mu_k \))