anonymous
  • anonymous
a spinner has 12 equal-size sector labeled 1 through 12.The spinner is spun once. what is the probability that it will land on a # greater than 3? express ur answer in as a decimal to the nearest hundreth
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Maddy1251
  • Maddy1251
Okay, we can write out what we have. :-) Or, set up inequalities to help us, right?
Maddy1251
  • Maddy1251
We have numbers 1-12. n<3 = 1, 2 n>3=4, 5, 6, 7, 8, 9, 10, 11, 12.
anonymous
  • anonymous
k

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Maddy1251
  • Maddy1251
Now that we have all that set up, we can set up a fraction to help us find our probability.
Maddy1251
  • Maddy1251
What set of numbers do you think we will use?
Maddy1251
  • Maddy1251
n<3 or n>3?
anonymous
  • anonymous
n>3?
Maddy1251
  • Maddy1251
Excellent! Because it is wanting to know the probability of the spinner landing on a number that is greater than 3, which is n>3 :-)
anonymous
  • anonymous
ok im starting to get it but then wat?
Maddy1251
  • Maddy1251
n>3 = 4, 5, 6, 7, 8, 9, 10, 11, 12 9/12. Since we have 9 numbers greater than 3.
Maddy1251
  • Maddy1251
That should simply down to 3/4.
Maddy1251
  • Maddy1251
That equals 0.75.
anonymous
  • anonymous
so the answer is 0.75?
Maddy1251
  • Maddy1251
From my calculations, yes.
Maddy1251
  • Maddy1251
It just says n>3, right? Now \[n \ge 3?\]
Maddy1251
  • Maddy1251
Not*
anonymous
  • anonymous
thank u so much!!!
Maddy1251
  • Maddy1251
You're welcome. :-]

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