If f(x) = 4x + 1 and g(x) = 3x + 2, what is f(g(x)) ?
a. 12x + 9
b. 12x + 7
c. 12x + 5
d. 12x + 3
What are the zeros of the polynomial function: f(x) = x3 - x2 - 6x ?
a. 0, -3, 2
b. 0, 3, -2
c. 0, -3, -2
d. 0, 3, 2
What are the possible number of negative zeros of f(x) = 2x7 - 2x6 + 7x5 - 7x4 - 4x3 + 4x2 ?
b. 2 or 0
c. 4, 2, or 0
d. 7, 5, 3, or 1
What polynomial has roots of -5, 2, and 4 ?
a. x3 - x2 - 22x + 40
b. x3 + x2 - 22x - 40
c. x3 + 3x2 - 18x - 40
d. x3 - 3x2 - 18x + 40
Stacey Warren - Expert brainly.com
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Yay! thank you so much. i have no clue what to do with these
meh too lazy...
@gabebae can you solve this one for me?
Find the polynomial f(x) that has the roots of -3, 5 of multiplicity 2. Explain how you would verify the zeros of f(x).
number 3 is b. 2 or 0
@askmelots can you try to solve the one i tagged gabe in because that ones more confusing
im doing that one now :)
A polynomial is a mathematical expression involving a sum of powers in one or more variables multiplied by coefficients. A polynomial in one variable (i.e., a univariate polynomial) with constant coefficients is given by
a_n x^n+...+a_2 x^2+a_1 x+a_0 .
So how would i use that to find the polynomial that has the roots -3, 5 of multiplicity 2?
The general technique for solving bigger-than-quadratic polynomials is pretty straightforward, but the process can be time-consuming.
The first step is to apply the Rational Roots Test to the polynomial to get a list of values that might possibly be solutions to the polynomial equation. You can follow this up with an application of Descartes' Rule of Signs, if you like, to narrow down which possible zeroes might be best to check. Of course, if you've got a graphing calculator, it's a good idea to do a quick graph, since x-intercepts of the graph are the same as zeroes of the equation. Seeing where the graph looks like it crosses the axis can quickly narrow down your list of possible zeroes.
so what would the polynomial be that has the roots -3,5 and multiplicity of 2?
im here...it just, this is too freaking confusing!
i know thats what i said to my teacher but she said i had to do it or i dont get credit. if you cant figure it out i can ask someone else.
I say you ask someone else, I tried the best i could, and your teacher is messed up XD
i know right haha, thanks for the other answers though
your welcome :(
im sorry I couldnt help you more :(