What are the possible remaining angle measures in triangle ABC with A=40, AC=60, and BC=45?
a.

Mathematics
**
**- anonymous

What are the possible remaining angle measures in triangle ABC with A=40, AC=60, and BC=45?
a.**
**

Mathematics
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Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
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- anonymous

What are the possible remaining angle measures in triangle ABC with A=40, AC=60, and BC=45?
a.**
**

Mathematics
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- anonymous

We can use the law of sines for this one. We have a side length and two angles. If we get back a sensible answer i.e. >0 and real valued then we should be good to go. The law of sines is
\[\frac{\sin(a)}{\alpha}=\frac{\sin(b)}{\beta}=\frac{\sin(c)}{\gamma} \]
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- anonymous

So what would it be?

- anonymous

Note: my law of sines is backwards. It should be
\[\frac{\sin(\alpha)}{a}\] and so on. Exchange all the letters and greek letters and you've got the correction

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- anonymous

Try the calculation and let me know what you come up with

- anonymous

I got C.

- anonymous

?

- anonymous

How might you go about checking your answer?

- anonymous

so its not right? i thought i did it right

- anonymous

I'm not telling you it is wrong. I am asking you might check your answer to make sure you are correct?

- anonymous

We would check it by determining all the angles of the triangle. If they sum to 180, then we are probably good. We can also check to see that this is correct in the law of sines or cosines.

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