nudeoua
  • nudeoua
Simplify this equation
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
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alekos
  • alekos
whats another way of writing \[3{\sqrt{21}} ?\]
tHe_FiZiCx99
  • tHe_FiZiCx99
\[3^{\frac{ 3 }{ 4 }} \times \sqrt[4]{7}\]
tHe_FiZiCx99
  • tHe_FiZiCx99
Mmm, if you wrote it correctly, that is. I can explain if you want, or just the easy way out

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Directrix
  • Directrix
I'd like to see the explanation or the gist of it.
tHe_FiZiCx99
  • tHe_FiZiCx99
Oh wait, I think I missed something
tHe_FiZiCx99
  • tHe_FiZiCx99
Sure, Direct
tHe_FiZiCx99
  • tHe_FiZiCx99
I'm having a time with LaTeX, so I'll use the basic form
tHe_FiZiCx99
  • tHe_FiZiCx99
hard time*
nudeoua
  • nudeoua
|dw:1446884563247:dw| This was the equation, my bad.
Directrix
  • Directrix
|dw:1446884685405:dw|
tHe_FiZiCx99
  • tHe_FiZiCx99
This changes everything :S Pretty simple, √(3) * √21 --> √(3*21) -- >63 √63 --> √(3^2 * 7) = 3√7
tHe_FiZiCx99
  • tHe_FiZiCx99
You see, you can find multiple factors for any large number, particularly if they aren't prime. 63 had a few, but 9 kept ringing for me; 9 * 7 = 63. √9 = 3, get it?
tHe_FiZiCx99
  • tHe_FiZiCx99
It's like a game, if you will :3
Directrix
  • Directrix
@tHe_FiZiCx99 On the first posted problem, did you get a result of (189)^(1/4) ?
tHe_FiZiCx99
  • tHe_FiZiCx99
No, but, I can change it to: 4√21 * √3. Lol, I'm sure you can guess how
tHe_FiZiCx99
  • tHe_FiZiCx99
Keep in mind that 4√21 is: |dw:1446885083565:dw|
Directrix
  • Directrix
I had that and then attempted to simplify to the fourth root of 189.
tHe_FiZiCx99
  • tHe_FiZiCx99
o i c :o
Directrix
  • Directrix
|dw:1446885154347:dw|

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