goalieboy
  • goalieboy
I will post the questions in the attachments
AP Chem
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
goalieboy
  • goalieboy
@Michele_laino
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Michele_Laino
  • Michele_Laino
hint: here the ratio moles of nitrogen over moles of ammonia is \(1:2\), the same goes for volume at STP conditions
goalieboy
  • goalieboy
@Rushwr can you see if you can help

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Rushwr
  • Rushwr
What do u think the answer is ?
goalieboy
  • goalieboy
I think that the answer is C because it seems to make sence
Rushwr
  • Rushwr
Yeah that's right :)
Rushwr
  • Rushwr
The molar ratio = the volume ratio
goalieboy
  • goalieboy
@michele_laino do you agree with me
Michele_Laino
  • Michele_Laino
yes! you are correct! It is option C, namely \(V=22.4\) liters
goalieboy
  • goalieboy
I think that this one is A
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Michele_Laino
  • Michele_Laino
first step: how many moles of glucose we have?
goalieboy
  • goalieboy
950 grams?
Michele_Laino
  • Michele_Laino
that is the starting mass of glucose, so the moles of glucose are: \[n = \frac{{950}}{{180}} = ...?\] \(180\) being the molecular weight of glucose
goalieboy
  • goalieboy
ok I am following you so far
Michele_Laino
  • Michele_Laino
please what is \(950/180=...?\)
goalieboy
  • goalieboy
5.27
goalieboy
  • goalieboy
that is what you get when you divide those two numbers
Michele_Laino
  • Michele_Laino
correct! we have \(5.278\) moles of glucose. Now, looking at your chemical reaction, we have \(6\) moles of consumed oxygen for every one mole of glucose, so your reaction happens, if the moles of oxygen are: \[{n_1} = 5.278 \cdot 6 = ...?\]
goalieboy
  • goalieboy
that would equal 31.668
Michele_Laino
  • Michele_Laino
correct!
goalieboy
  • goalieboy
no what do we do
Michele_Laino
  • Michele_Laino
finally, being \(16\) grams the weigh of one mole of oxygen, then the requested quantity of oxygen which has to be consumed is: \[m = 31.668 \cdot 16 = ...?\]
Michele_Laino
  • Michele_Laino
weight*
goalieboy
  • goalieboy
that would equal 506.668
Michele_Laino
  • Michele_Laino
please wait, we have to consider the molecular weight of the molecular oxygen, so the correct quantity of oxygen is: \[m = 31.668 \cdot 32 = ...?\] since the molecular weight of molecular oxygen is \(16 \cdot 2=32\)
goalieboy
  • goalieboy
do you want the answer to that?
Michele_Laino
  • Michele_Laino
what is \(31.668 \cdot 32=...?\)
goalieboy
  • goalieboy
1013.376
Michele_Laino
  • Michele_Laino
so, what is the right option?
goalieboy
  • goalieboy
C
Michele_Laino
  • Michele_Laino
correct!
goalieboy
  • goalieboy
can you help me with three more
Michele_Laino
  • Michele_Laino
ok! Please close this question and open a new one

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