anonymous
  • anonymous
Given: m∠PQR = x − 7, m∠SQR = x − 1, and m∠PQS = 100. Find x. The image is of three lines QR, QS and QP originating from a common point Q. QS is horizontal, QR is making acute angle with QS and QP is making obtuse angle with QS. m∠POR + m∠SQR − m∠PQS a. _____ x − 7 + x − 1 = 100 b. Substitution Property 2x − 8 = 100 c. Simplify. 2x = 108 d. _____ x = 54 e. Division Property of Equality
Geometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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jim_thompson5910
  • jim_thompson5910
So something like this I'm guessing |dw:1446943176442:dw|
anonymous
  • anonymous
yes
anonymous
  • anonymous
can you help fill in the blank

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jim_thompson5910
  • jim_thompson5910
when you wrote `m∠POR + m∠SQR − m∠PQS` I'm assuming you meant to write this `m∠PQR + m∠SQR = m∠PQS`
jim_thompson5910
  • jim_thompson5910
the first line is Angle Addition Postulate http://hotmath.com/hotmath_help/topics/angle-addition-postulate.html it's the idea of gluing two angles together to form a bigger angle
jim_thompson5910
  • jim_thompson5910
what are your thoughts on the second blank?
anonymous
  • anonymous
I have no idea
jim_thompson5910
  • jim_thompson5910
what is happening to both sides when we go from `2x - 8 = 100` to `2x = 108` are we subtracting something from both sides? adding? multiplying? or something else?
anonymous
  • anonymous
never mind its addition property of equality
jim_thompson5910
  • jim_thompson5910
yes, we add 8 to both sides

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