anonymous
  • anonymous
WILL MEDAL AND FAN!!! John and Mike are carpooling to see their favorite baseball team play. On their way to the game, they drove 60 miles in the first 45 minutes of the trip. Unfortunately then they ran into heavy traffic and were only able to travel at a constant speed of 20 miles per hour. Choose the correct function which describes the average speed during the entire trip as a function of time, h, in hours. Question 6 options: f(h)=60+20(h−0.75)h where h≥0.75 f(h)=20h+1.3 f(h)=60h+20 f(h)=60h+45h
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
@SolomonZelman could you help? ill medal.:)
anonymous
  • anonymous
@superdavesuper
jim_thompson5910
  • jim_thompson5910
Were you able to figure out how far they traveled at any given time h ?

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More answers

anonymous
  • anonymous
well at least 45, i was thinking its option D?
jim_thompson5910
  • jim_thompson5910
so they travel 60 mi in the first part of their trip how far do they travel on the second part?
anonymous
  • anonymous
20mph
anonymous
  • anonymous
other than that we dont know
jim_thompson5910
  • jim_thompson5910
that's the speed for the second part
jim_thompson5910
  • jim_thompson5910
let's say they travel 20 mph for h hrs the distance would be 20*h, no?
anonymous
  • anonymous
yes
anonymous
  • anonymous
so b?
jim_thompson5910
  • jim_thompson5910
here's the thing though: they didn't travel a full h hours for 20 mph they spent the first 0.75 hrs going some speed (first part of the trip) then the rest of the h-0.75 hrs is them going 20 mph
jim_thompson5910
  • jim_thompson5910
so they travel 60 mi on the first leg of the trip then an additional 20(h-0.75) for the second leg
jim_thompson5910
  • jim_thompson5910
in total, they travel a distance of `60 + 20(h - 0.75)` miles
jim_thompson5910
  • jim_thompson5910
to find the average speed over the entire trip, you divide that total distance by the total time (in this case, h) so the average speed is \(\Large \frac{60 + 20(h - 0.75)}{h}\) mph
anonymous
  • anonymous
ohh huh i wouldnt have guessed that...
anonymous
  • anonymous
thank you:)
jim_thompson5910
  • jim_thompson5910
yeah it's probably not the most intuitive thing out there, but just remember distance = rate*time rate = distance/time "rate" is another term for "speed"

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