anonymous
  • anonymous
Algebra 1 - Simplifying Expressions (will award and fan asap)
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
4ab + 7ba - 5 -3ba + 9 -2ab
hysusonic
  • hysusonic
do you know how to combine like terms?
anonymous
  • anonymous
Yes. So I do that first? But ab and ba aren't like terms, right?

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hysusonic
  • hysusonic
i'm not 100% sure but i think the teacher put that to confuse you bc multiplication is multiplication no matter the order
anonymous
  • anonymous
Oh.. well I kinda gotta know for sure
anonymous
  • anonymous
@satellite73
jim_thompson5910
  • jim_thompson5910
like hysusonic is saying, ab = ba since you can multiply two numbers in any order
jim_thompson5910
  • jim_thompson5910
so -3ba is the same as -3ab
anonymous
  • anonymous
Oh ok! Thanks!
anonymous
  • anonymous
So can you draw out the steps so I can see how you simplify it?
anonymous
  • anonymous
I'm a visual learner
jim_thompson5910
  • jim_thompson5910
7ba would be equal to ???
anonymous
  • anonymous
huh? what are you asking? 7ab?
jim_thompson5910
  • jim_thompson5910
yes 7ab
jim_thompson5910
  • jim_thompson5910
so `4ab + 7ba - 5 -3ba + 9 -2ab` is the same as `4ab + 7ab - 5 -3ab + 9 -2ab`
jim_thompson5910
  • jim_thompson5910
|dw:1446948863848:dw|
anonymous
  • anonymous
omg thats so helpful
jim_thompson5910
  • jim_thompson5910
|dw:1446948872061:dw|
anonymous
  • anonymous
so in total 6ab?
jim_thompson5910
  • jim_thompson5910
|dw:1446948899099:dw|
jim_thompson5910
  • jim_thompson5910
yes if you combine all the terms with "ab" in them, then you get 6ab
anonymous
  • anonymous
Ok wait so the answer is 6ab -4?
jim_thompson5910
  • jim_thompson5910
very close
anonymous
  • anonymous
+4
jim_thompson5910
  • jim_thompson5910
the constant terms are -5 and +9 they combine to +4
jim_thompson5910
  • jim_thompson5910
yes so you'll have 6ab + 4
anonymous
  • anonymous
You're so helpful! ok I have another question can you help?
jim_thompson5910
  • jim_thompson5910
sure go ahead
anonymous
  • anonymous
\[-4 ^{2} - (-2) ^{3} - (-2) ^{2} + \sqrt[3]{27} \]
jim_thompson5910
  • jim_thompson5910
the small 2 up top means "square" when you square a number, you multiply it by itself twice in this case, \(\Large 4^2 = 4*4 = 16\) so \(\Large -4^2 = -16\)
jim_thompson5910
  • jim_thompson5910
the small 3 is like squaring, but it's called "cubing" cubing a number means you multiply the number by itself 3 times \[\Large (-2)^3 = (-2)*(-2)*(-2) = 8\]
jim_thompson5910
  • jim_thompson5910
make sense so far?
anonymous
  • anonymous
yup
jim_thompson5910
  • jim_thompson5910
any guesses as to what \(\LARGE \sqrt[3]{27}\) means?
jim_thompson5910
  • jim_thompson5910
it's similar to a square root
anonymous
  • anonymous
is the answer 9?
jim_thompson5910
  • jim_thompson5910
no
anonymous
  • anonymous
I have no idea lol
jim_thompson5910
  • jim_thompson5910
\(\LARGE \sqrt[3]{27}\) means the cube root of 27 what number, when you multiply it by itself three times, gives you 27?
anonymous
  • anonymous
3?
jim_thompson5910
  • jim_thompson5910
yes, so \(\LARGE \sqrt[3]{27} = 3\)
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
so can you draw out how I would simply the equation?
anonymous
  • anonymous
simplify*
anonymous
  • anonymous
I'll do the problem too so we can see if we get the same answer
jim_thompson5910
  • jim_thompson5910
so \(\Large -4 ^{2} - (-2) ^{3} - (-2) ^{2} + \sqrt[3]{27}\) turns into \(\Large -16 - (-8) - 4 + 3\) sorry I made a typo earlier I meant to say \(\Large (-2)^3 = (-2)*(-2)*(-2) = -8\)
anonymous
  • anonymous
yes, i have that so far
anonymous
  • anonymous
can it be simplified any further?
jim_thompson5910
  • jim_thompson5910
−16−(−8)−4+3 then turns into −16+8−4+3 I'll let you finish up
anonymous
  • anonymous
-9?
jim_thompson5910
  • jim_thompson5910
yep that's the final answer
anonymous
  • anonymous
great!!!
anonymous
  • anonymous
I have a few more questions but I'll tag you when I get to them ok?

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