anonymous
  • anonymous
expand using the distributive property: (will award and fan asap)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
\[a ^{2}b(xa ^{2}b + a ^{4}b)\]
anonymous
  • anonymous
@jim_thompson5910
anonymous
  • anonymous
@Nnesha

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jim_thompson5910
  • jim_thompson5910
what do you have so far?
anonymous
  • anonymous
[a ^{2}b(xa ^{2}b) + a ^{2}b (a ^{4}b)\]
anonymous
  • anonymous
oh wait thats messed up hold on
anonymous
  • anonymous
\[a ^{2}b(xa ^{2}b) + a ^{2}b (a ^{4}b) \]
anonymous
  • anonymous
is that right so far? @jim_thompson5910
jim_thompson5910
  • jim_thompson5910
yes so far, so good you used the distributive property in the right way
anonymous
  • anonymous
phew
jim_thompson5910
  • jim_thompson5910
are you able to multiply out the terms?
anonymous
  • anonymous
Am I? This problem looks so confusing
jim_thompson5910
  • jim_thompson5910
let's start with this |dw:1446951040302:dw|
jim_thompson5910
  • jim_thompson5910
there are really 1s over the b terms |dw:1446951080115:dw|
anonymous
  • anonymous
yup I'm following so far :)
jim_thompson5910
  • jim_thompson5910
to multiply this out, we just group up the 'a' terms and add the exponents |dw:1446951109457:dw|
jim_thompson5910
  • jim_thompson5910
same with the b terms |dw:1446951146595:dw|
anonymous
  • anonymous
oh so |dw:1446951177692:dw|
anonymous
  • anonymous
is the answer for the first part?
jim_thompson5910
  • jim_thompson5910
yes then you will do the same for the other pair of terms being multiplied
anonymous
  • anonymous
ok so its |dw:1446951314864:dw|
jim_thompson5910
  • jim_thompson5910
yep \(\Large a^6b^2\)
anonymous
  • anonymous
so now I add those two parts together?
jim_thompson5910
  • jim_thompson5910
yep to get \(\LARGE a^4b^2x + a^6b^2\) we cannot combine the terms because they are not like terms
anonymous
  • anonymous
we can't add those?
jim_thompson5910
  • jim_thompson5910
no we cannot
jim_thompson5910
  • jim_thompson5910
it's like 2x + 3y
anonymous
  • anonymous
\[a ^{4} a ^{6}\] are like terms
jim_thompson5910
  • jim_thompson5910
each needs to have `a^4b^2x` or `a^6b^2`
anonymous
  • anonymous
i'm confused? but ok I'll take your word for it
jim_thompson5910
  • jim_thompson5910
if you had something like `7a^4b^2x + 3a^4b^2x` then it would turn into `10a^4b^2x` notice how each term has a `a^4b^2x` attached to the coefficient
anonymous
  • anonymous
ohh ok got it :)
jim_thompson5910
  • jim_thompson5910
I'm glad it makes more sense now

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