anonymous
  • anonymous
the perimeter of a rectangle is 56m. if the width were doubled and the length were increased by 8m, then the perimeter would be 82m. what are the dimensions
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Directrix
  • Directrix
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Directrix
  • Directrix
Perimeter of a rectangle is 2*x + 2*y. First Rectange: 2*x + 2*y = 56 Second Rectangle: 2*(2x) + 2*(y + 8) = 82
Directrix
  • Directrix
2*x + 2*y = 56 2*(2x) + 2*(y + 8) = 82 Solve those two simultaneous equations to solve for x and y. @Bweezy5

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anonymous
  • anonymous
WOOT! i was going the right way thank you very much! :D

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