gabrielah96
  • gabrielah96
solve for x. log(x+12)=2log(x)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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campbell_st
  • campbell_st
well you can rewrite them using log laws \[lof(x +12) = \log(x^2)\] then raise each side as a power of the base and you then need to solve x + 12 = x^2 or x^2 - x - 12 = 0 now solve for x. hope it helps
lochana
  • lochana
that's right now you can factorize it easily x^2 -x -12 = (x - 4)(x + 3) x = 4 and -3
ganeshie8
  • ganeshie8
reject -3 because we need `x > 0` for the expression `log(x)` to be real

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campbell_st
  • campbell_st
are you sure about x = -3 log (-3 + 12) = log((-3)^2) I think you have to include x = -3 as a solution
campbell_st
  • campbell_st
it's always an interesting question...
ganeshie8
  • ganeshie8
\(\log(x^2)\) is not necessarily same as \(2\log x\)
ganeshie8
  • ganeshie8
that holds only when \(x\) is positive
ganeshie8
  • ganeshie8
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gabrielah96
  • gabrielah96
thanks everyone!

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