anonymous
  • anonymous
Hellpp!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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mathmate
  • mathmate
If mBC is real, then there is an infinite number of possible values. If mBC is integer (i.e. counting numbers), then you can work that out using the triangle inequality: The sum of any two sides of a triangle is greater than the third side, which I can make a corollary as: The sum of the two shorter sides of a triangle must be greater than the third side. But here you have another constraint, which is the sum of the two base angles must not be obtuse. |dw:1447070756509:dw|
mathmate
  • mathmate
|dw:1447070800826:dw| From the diagram, we see that (x+y)<90 degrees is another constraint, this means that angle D must be obtuse. The Pythagoras theorem will express this inequality as: (mBC)^2>8^2+15^2 This provides the lower bound of mBC, while the triangle inequality gives the upper bound.

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anonymous
  • anonymous
then mBC>17; 7
anonymous
  • anonymous
@mathmate
mathmate
  • mathmate
|dw:1447076838365:dw| :)

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