kingkas
  • kingkas
A mass of 0.75 kg is attached to a spring and placed on a horizontal surface. The spring has a spring constant of 180 N/m, and the spring is compressed 0.3 m past its natural length. If the mass is released from this compressed position, what is the speed of the mass as it passes the natural length of the spring? A. 4.6 m/s B. 0.83 m/s C. 3.8 m/s D. 2.1 m/s
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
We can use the conservation of energy to solve this problem! Initially, we're giving it spring potential energy. There's no kinetic energy yet because it's not releasing the energy in a form of movement! When we release the spring, all the potential energy is converted into kinetic energy! \[\huge KE_0+PE_0=KE_f+PE_f\] We already stated that there's no initial kinetic and no final potential, therefore \[\huge PE_0=KE_f\]\[\huge \frac{ 1 }{ 2 }k(\Delta x)^2=\frac{ 1 }{ 2 }mv^2\] Solve for v! :) Also, notice here that there's no gravitational potential energy because we're not concerned here with changing it's position vertically. If we were to observe the block being shot from compressed spring up a ramp, then we would have to include the gravitational energy.
kingkas
  • kingkas
Can you help with filling in the variables? I'm really confused.
kingkas
  • kingkas
@CShrix

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
k is the spring constant the change in x is the change in length of the spring due to compression/tension m is the mass v is the velocity (which you're supposed to find) Using basic algebra techniques, you can isolate v to find a solution.

Looking for something else?

Not the answer you are looking for? Search for more explanations.