rebeccaxhawaii
  • rebeccaxhawaii
hey i have an Algebra 2 question
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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jango_IN_DTOWN
  • jango_IN_DTOWN
bring it on
rebeccaxhawaii
  • rebeccaxhawaii
If a football player passes a football from 4 feet off the ground with an initial velocity of 36 feet per second, how long will it take the football to hit the ground? Use the equation h = -16t2 + 36t + 4
jango_IN_DTOWN
  • jango_IN_DTOWN
h = -16t² + 36t + 4. When h= 0, we have 0= -16t² + 36t + 4. or 16t² − 36t − 4.=0 or 4t² − 9t − 1.=0 →t=[ − (−9)±√{(−9)²− 4×4×(− 1)}]/(2×4) =[ 9 ±√{81+ 16}]/(8) =[ 9±√{97}]/(8) =2. 356 Seconds

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jango_IN_DTOWN
  • jango_IN_DTOWN
it will hit the ground when h=0
jango_IN_DTOWN
  • jango_IN_DTOWN
from it we caluculate for t, with the help of the given equation/ you will get two values: one positive and another one negative, but time cannot be negative. so we will take the positive value
rebeccaxhawaii
  • rebeccaxhawaii
so h = -16t2 + 36t + 4= 0 is in standard form by converting it into a quadratic equation will give me my answer right ?
jango_IN_DTOWN
  • jango_IN_DTOWN
yeah right by putting h=0
rebeccaxhawaii
  • rebeccaxhawaii
k thanks one more thing i was trying to solve this but i didnt get the right answer
jango_IN_DTOWN
  • jango_IN_DTOWN
ok tell me
rebeccaxhawaii
  • rebeccaxhawaii
h = -16t2 + 36t + 4
rebeccaxhawaii
  • rebeccaxhawaii
can you use the equation button by the typing box pllllssssssssssss when explaining it makes it easier to comprehend
jango_IN_DTOWN
  • jango_IN_DTOWN
do you want me to solve it again? i mean the quadratic equation?
rebeccaxhawaii
  • rebeccaxhawaii
yes pls
jango_IN_DTOWN
  • jango_IN_DTOWN
we have \[-16t^2+36t+4=0\] divide throughout by -4 and you have \[4t^2-9t-1=0\]
jango_IN_DTOWN
  • jango_IN_DTOWN
now you solve this quadratic
rebeccaxhawaii
  • rebeccaxhawaii
no wait sorry
rebeccaxhawaii
  • rebeccaxhawaii
3x2 = 7x - 3
rebeccaxhawaii
  • rebeccaxhawaii
3^2=7x-3
jango_IN_DTOWN
  • jango_IN_DTOWN
\[3x^2=7x-3\] implies \[3x^2-7x+3=0\]
rebeccaxhawaii
  • rebeccaxhawaii
can u solve it though
jango_IN_DTOWN
  • jango_IN_DTOWN
yeah obviously. The general quadratic form is \[ax^2+bx+c=0\] where a, b,c are constants. and the solution is given by \[x=(-b \pm \sqrt{b^2-4ac})/2a\]
rebeccaxhawaii
  • rebeccaxhawaii
mhmm
jango_IN_DTOWN
  • jango_IN_DTOWN
here a=3,b=-7,c=3 now plug in the values of a,b,c in the above formula
jango_IN_DTOWN
  • jango_IN_DTOWN
the answer is \[x=(7\pm \sqrt{13})/6\]
jango_IN_DTOWN
  • jango_IN_DTOWN
@rebeccaxhawaii
rebeccaxhawaii
  • rebeccaxhawaii
howd you get 13 i got 43
jango_IN_DTOWN
  • jango_IN_DTOWN
\[(-7)^2-4*3*3=49-36=13\]
rebeccaxhawaii
  • rebeccaxhawaii
oh duh i forgot about the exponent thanks
jango_IN_DTOWN
  • jango_IN_DTOWN
n.p.
jango_IN_DTOWN
  • jango_IN_DTOWN
ok bye. @rebeccaxhawaii
rebeccaxhawaii
  • rebeccaxhawaii
WAIT
rebeccaxhawaii
  • rebeccaxhawaii
@jango_IN_DTOWN
jango_IN_DTOWN
  • jango_IN_DTOWN
ok.. but tell me fast
rebeccaxhawaii
  • rebeccaxhawaii
what did you get when solving the football player one
jango_IN_DTOWN
  • jango_IN_DTOWN
2.356secs approx
rebeccaxhawaii
  • rebeccaxhawaii
no no just in quadratic form what was the form
jango_IN_DTOWN
  • jango_IN_DTOWN
\[4t^2-9t-1=0\]
rebeccaxhawaii
  • rebeccaxhawaii
no the quadradic formula
jango_IN_DTOWN
  • jango_IN_DTOWN
Which part I cant get you
rebeccaxhawaii
  • rebeccaxhawaii
what is the equation in quadratic form
jango_IN_DTOWN
  • jango_IN_DTOWN
-16t² + 36t + 4.=0
rebeccaxhawaii
  • rebeccaxhawaii
no thats standard
jango_IN_DTOWN
  • jango_IN_DTOWN
h = -16t² + 36t + 4. When h= 0, we have 0= -16t² + 36t + 4. or 16t² − 36t − 4.=0 or 4t² − 9t − 1.=0 →t=[ − (−9)±√{(−9)²− 4×4×(− 1)}]/(2×4) =[ 9 ±√{81+ 16}]/(8) =[ 9±√{97}]/(8) =2. 356 Seconds
rebeccaxhawaii
  • rebeccaxhawaii
no i just need the equation that is in standard form converted into quadratic form
jango_IN_DTOWN
  • jango_IN_DTOWN
ohkar ax^2+bx+c=0
rebeccaxhawaii
  • rebeccaxhawaii
that is standard i need it in quadratic
jango_IN_DTOWN
  • jango_IN_DTOWN
\[x=(-b \pm \sqrt{b^2-4ac})/2a\]
rebeccaxhawaii
  • rebeccaxhawaii
yes what is the equation when converted to that form
jango_IN_DTOWN
  • jango_IN_DTOWN
it is the solution of the standard form
rebeccaxhawaii
  • rebeccaxhawaii
no can you convert -16t² + 36t + 4=0 into quadratic form
jango_IN_DTOWN
  • jango_IN_DTOWN
ok divide throught y -4 and you have \[4t^2-9t-1=0\]
jango_IN_DTOWN
  • jango_IN_DTOWN
\[t={-(-9)\pm \sqrt{(-9)^2-4*4*(-1)}}/(2*4)\]
rebeccaxhawaii
  • rebeccaxhawaii
why is it like that now ?
rebeccaxhawaii
  • rebeccaxhawaii
it was postitves before
jango_IN_DTOWN
  • jango_IN_DTOWN
here b=-9 which is negative
rebeccaxhawaii
  • rebeccaxhawaii
but why did it change ?
jango_IN_DTOWN
  • jango_IN_DTOWN
we divided by -4.. so a negative came
rebeccaxhawaii
  • rebeccaxhawaii
thank you so much @jango_IN_DTOWN

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