Aizhalee
  • Aizhalee
ALGEBRA HELP (f•g)(1) and (g•f)(-1)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Aizhalee
  • Aizhalee
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Aizhalee
  • Aizhalee
@jim_thompson5910 help please
johnweldon1993
  • johnweldon1993
Hey! idk why that got deleted! lol \[\large (f\cdot g)(1) \rightarrow f(g(1))\]

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jim_thompson5910
  • jim_thompson5910
Is it \[\Large (f \cdot g)(1)\] or is it \[\Large (f \circ g)(1)\]??
Aizhalee
  • Aizhalee
theres two questions for the graph the first one is (f•g)(1) the second question is (g•f)(-1)
jim_thompson5910
  • jim_thompson5910
If it is \[\Large (f \cdot g)(1)\] then \[\Large (f \cdot g)(1) = f(1) \cdot g(1)\]
Aizhalee
  • Aizhalee
Ok I'm writing this in my notebook
jim_thompson5910
  • jim_thompson5910
to find the value of f(1), you look at the y coordinate of the point on f(x) when x = 1 to find the value of g(1), you look at the y coordinate of the point on g(x) when x = 1
Aizhalee
  • Aizhalee
yes . I look and I see that g(x) y coordinate is -5 am I right ?
jim_thompson5910
  • jim_thompson5910
yes (1,-5) is a point on g(x)
Aizhalee
  • Aizhalee
wow :) yay and for f(x) is 3
jim_thompson5910
  • jim_thompson5910
yes
Aizhalee
  • Aizhalee
:D Yay . so how do I right this in the function ?
Aizhalee
  • Aizhalee
is that the answer ?
jim_thompson5910
  • jim_thompson5910
no
jim_thompson5910
  • jim_thompson5910
to find the value of f(1), you look at the y coordinate of the point on f(x) when x = 1 that y coordinate is 3, so f(1) = 3 to find the value of g(1), you look at the y coordinate of the point on g(x) when x = 1 that y coordinate is -5, so g(1) = -5
jim_thompson5910
  • jim_thompson5910
f(1) = 3 g(1) = -5 \[\Large (f \cdot g)(1) = f(1) \cdot g(1)\] \[\Large (f \cdot g)(1) = 3 \cdot (-5)\] \[\Large (f \cdot g)(1) = -15\]
Aizhalee
  • Aizhalee
I was just about to ask that lol . Thanks a lot Professor Jiim for helping me learn this :)
jim_thompson5910
  • jim_thompson5910
you're welcome
Aizhalee
  • Aizhalee
ok what about the second question the negative 1 I do the same exact thing

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