tootzrll
  • tootzrll
someone please help me on this... Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the distance in 1.5 h. Car B traveled 15 mph faster than Car A. How fast did Car B travel?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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IrishBoy123
  • IrishBoy123
\(x_A = v_A \times t_A\) \(x_B = v_B \times t_B\) \(x_A = x_B \implies v_A \times t_A = v_B \times t_B\) \(t_A = 2, \; t_B = 1.5\) \(v_B = v_A + 15\) that kind of stuff :p
tootzrll
  • tootzrll
bruuuuhh im never gonna pass this... D,X
IrishBoy123
  • IrishBoy123
you know that \(distance = speed \times time\)? right?

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tootzrll
  • tootzrll
yes...
IrishBoy123
  • IrishBoy123
ok so they travel the same distance, right? at different speeds and using different times.
tootzrll
  • tootzrll
yes
IrishBoy123
  • IrishBoy123
so, ..., distance travelled by car A is \(v \times 2 \) where v is the speed of the car A
tootzrll
  • tootzrll
yes
IrishBoy123
  • IrishBoy123
and that same distance, as travelled by car B, is \( (v+15)×1.5\) that might be the confusing part...
tootzrll
  • tootzrll
wait, so whats the whole equation so far? i might have it by now...
IrishBoy123
  • IrishBoy123
they travel the same distance so you can say that \[v \times 2 = (v+15)×1.5\] or \(2v = 1.5(v+15)\)
IrishBoy123
  • IrishBoy123
http://www.wolframalpha.com/input/?i=solve%2C+2v+%3D+1.5%28v%2B15%29
tootzrll
  • tootzrll
thanks a lot!! x)))
IrishBoy123
  • IrishBoy123
v is the speed of car A and you need the speed of car B mentioned just in case
IrishBoy123
  • IrishBoy123
\(v_B = v + 15\)

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