SPHott51
  • SPHott51
Solve log(3x+5) =0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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freckles
  • freckles
0=log(1)
freckles
  • freckles
again if log(a)=log(b) then a=b
freckles
  • freckles
replace 0 with log(1) as suggested in my first post and then use my second post to solve a linear equation

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freckles
  • freckles
untrue |dw:1447125672052:dw|
xapproachesinfinity
  • xapproachesinfinity
that is just a disguized linear equation 3x+5=1 like @freckles mentioned log1=0 so what inside log must equal to 1 for that to happen
SolomonZelman
  • SolomonZelman
I was thinking of somthing else..
xapproachesinfinity
  • xapproachesinfinity
lol @SolomonZelman sometimes i do such mistakes hahaha
xapproachesinfinity
  • xapproachesinfinity
the other i had cal iii exam i did a severe mistake like that hhhhhh i know the answer yet i went for the wrong thing lol
xapproachesinfinity
  • xapproachesinfinity
the other day*
SolomonZelman
  • SolomonZelman
I overthought and started to talk nonsense
SPHott51
  • SPHott51
Okay so what do you mean? Like log3x +log5 =0..?
freckles
  • freckles
no @SPHott51
xapproachesinfinity
  • xapproachesinfinity
nn dear that is not true at all about logs
freckles
  • freckles
log(1) is 0 so replace 0 with log(1) log(3x+5)=log(1) implies 3x+5=1 solve 3x+5=1 for x
xapproachesinfinity
  • xapproachesinfinity
i wrote the equation above 3x+5=1
freckles
  • freckles
maybe he got confused from all the other stuff being posted about the domain versus range thing @xapproachesinfinity
xapproachesinfinity
  • xapproachesinfinity
i guess :) hopefully it is clearer now
freckles
  • freckles
though that bit is also important to know :p
SPHott51
  • SPHott51
AGHH, I always make things harder for myself
xapproachesinfinity
  • xapproachesinfinity
think of log in association with exponential since they are inverse of each other to make your life easier
xapproachesinfinity
  • xapproachesinfinity
for instance we know that (anything)^0=1 so log1=0 it is important to understand this bond
xapproachesinfinity
  • xapproachesinfinity
for porperties of log(ab)=loga +logb for instance came from the fact that 10^(a+b)=10^a 10^b (im using log base 10 here, but it really does not matter for properties of logs)

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