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again if log(a)=log(b) then a=b
replace 0 with log(1) as suggested in my first post and then use my second post to solve a linear equation
that is just a disguized linear equation 3x+5=1 like @freckles mentioned log1=0 so what inside log must equal to 1 for that to happen
I was thinking of somthing else..
lol @SolomonZelman sometimes i do such mistakes hahaha
the other i had cal iii exam i did a severe mistake like that hhhhhh i know the answer yet i went for the wrong thing lol
the other day*
I overthought and started to talk nonsense
Okay so what do you mean? Like log3x +log5 =0..?
nn dear that is not true at all about logs
log(1) is 0 so replace 0 with log(1) log(3x+5)=log(1) implies 3x+5=1 solve 3x+5=1 for x
i wrote the equation above 3x+5=1
maybe he got confused from all the other stuff being posted about the domain versus range thing @xapproachesinfinity
i guess :) hopefully it is clearer now
though that bit is also important to know :p
AGHH, I always make things harder for myself
think of log in association with exponential since they are inverse of each other to make your life easier
for instance we know that (anything)^0=1 so log1=0 it is important to understand this bond
for porperties of log(ab)=loga +logb for instance came from the fact that 10^(a+b)=10^a 10^b (im using log base 10 here, but it really does not matter for properties of logs)