tayaiv
  • tayaiv
Triangle ABC has side lengths: √6, √2, and 2√2 units. If the base of the triangle has a length of √6, what is the measure of the base angle? I'm not entirely sure which base angle the question is talking about. Thanks!
Mathematics
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SOLVED
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chestercat
  • chestercat
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dayakar
  • dayakar
|dw:1447156921584:dw|
dayakar
  • dayakar
\[a= \sqrt{6}, b= \sqrt{2}, c= 2\sqrt{2}\]
lochana
  • lochana
this is a right triangle. because side lengths obey pythsgoras theorem (2root(2))^2 = 6 + 2 8 = 8

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lochana
  • lochana
|dw:1447157432095:dw|
dayakar
  • dayakar
\[\cos A = \frac{ b ^{2}+c ^{2}-a ^{2} }{ 2bc}\]
dayakar
  • dayakar
u r right I used above formula
lochana
  • lochana
sorry . it is cosx. not sinx. so cosx = root(3)/2 x = 30 degrees :)
tayaiv
  • tayaiv
Thank you so much!! @lochana @dayakar

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