Maddy1251
  • Maddy1251
Solve for 'x' in the equation 300=200e^0.3x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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imqwerty
  • imqwerty
try dividing both sides by 200 then u take log on both sides with base e
Maddy1251
  • Maddy1251
@imqwerty \[1.5=e^{0.3x}\] Is that a good start
imqwerty
  • imqwerty
yes

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imqwerty
  • imqwerty
are u allowed to use calculators?
Maddy1251
  • Maddy1251
Yes
imqwerty
  • imqwerty
ok now try doing this- we take log with base e on both sides \[\log_{e}1.5=\log_{e}e^{0.3x}\]
Maddy1251
  • Maddy1251
Would that be like taking log 1.5? @imqwerty
imqwerty
  • imqwerty
can u tell what is the base of logarithm in this^
Maddy1251
  • Maddy1251
Well it has base 'e' right?
imqwerty
  • imqwerty
yes we are taking base e we take base as e in this case so that the right hand side of the equation can be simplified easily :)
imqwerty
  • imqwerty
if u get confused somewhere feel free to ask
Maddy1251
  • Maddy1251
@imqwerty is the answer bout 1.35?
imqwerty
  • imqwerty
yeah its 1.35
Maddy1251
  • Maddy1251
Okay awesome! For \[1500=25 \times 2^{0.45x}=23.58?\]
Maddy1251
  • Maddy1251
Approx. that is.
imqwerty
  • imqwerty
try doin it again :) i think theres a lil mistake
imqwerty
  • imqwerty
to check your answers ...to see if they are correct u jst try putting the value of x that ur getting into the equation :) liek here u got x=23.58 approx when u put it in the equation 25x2^{0.45x} 25x 2^{0.45x23.58} =39099.328 so this is not 1500 therefore x=23.58 is wrong

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