anonymous
  • anonymous
What is the oblique asymptote of the function f(x) = the quantity of x squared plus x minus 2, all over x plus 1? y = x + 3 y = x y = x − 1 y = x − 3
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
@DanJS
anonymous
  • anonymous
@zepdrix
DanJS
  • DanJS
do you see why this may have an oblique asmytope from inspection? \[\large f(x) = \frac{ x^2+x-2 }{ x+1 }\]

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anonymous
  • anonymous
um i think so but im not sure
DanJS
  • DanJS
notice the highest powers of each , top and bottom.. If the top is larger 2 > 1, there may be a slant asmytpoe
DanJS
  • DanJS
You can divide the bottom into the top in this case... do you know how to start that?
anonymous
  • anonymous
no i dont
DanJS
  • DanJS
Start by drawing this |dw:1447183301355:dw|
anonymous
  • anonymous
ima rewrite what you do on paper
DanJS
  • DanJS
like normal division with numbers... what do you need to multiply x by to get x^2? x, put that in the top, then multiply (x+1) by that , and subtract...
anonymous
  • anonymous
brb i gotta use the batroom
DanJS
  • DanJS
|dw:1447183589896:dw| this one was easy, one step, you get a -2/(x+1) remainder, which doesnt matter here, yhou just want the part that makes up the line...
DanJS
  • DanJS
respond if you dont understand...
DanJS
  • DanJS
you can always graph the thing to check if it looks right...
DanJS
  • DanJS
https://www.desmos.com/calculator

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