anonymous
  • anonymous
need help with this, use the geometric series test, from one to inifinty of (-3/2)^n, i got it was convergent, but just want to check my work
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
freckles
  • freckles
you do know that \[\frac{-3}{2} \cancel{\in} (-1,1)\]
freckles
  • freckles
?
anonymous
  • anonymous
see that, is where i dont understand, how do you know that, i have looked at samples of the geo test, but everytime i use it, i get it wrong, but i use the test correctly

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

freckles
  • freckles
how do i know the number -3/2 is not between -1 and 1?
anonymous
  • anonymous
yes, i see that
freckles
  • freckles
oh then what does "how do you know that" refer to?
anonymous
  • anonymous
how to show with the geometric test, like how do i show my work with that, not trying to make you do the work, just how do i prove that
freckles
  • freckles
r has to between -1 and 1 for it to converge
freckles
  • freckles
r being the common ratio
freckles
  • freckles
otherwise it diverges
freckles
  • freckles
that is the test
anonymous
  • anonymous
is it really that simple?
freckles
  • freckles
yep
anonymous
  • anonymous
then why do teachers make it so gosh dang more complicated
freckles
  • freckles
example \[\sum_{n=1}^{\infty } (\frac{1}{2})^n \text{ this one converges because } \frac{1}{2} \in (-1,1)\]
freckles
  • freckles
example \[\sum_{n=1}^{\infty} (\frac{-1}{2})^n \text{ also converges because } \frac{-1}{2} \in (-1,1)\]
anonymous
  • anonymous
so since that it is not between -1 and 1, it diverges
freckles
  • freckles
http://tutorial.math.lamar.edu/Classes/CalcII/Series_Special.aspx don't know if you ever heard of pauls notes but he has really great notes :)
freckles
  • freckles
right
anonymous
  • anonymous
thank you, that makes a lot more sense, looking at notes and books, this is the easiest explanation i have heard
anonymous
  • anonymous
and no, i havent
freckles
  • freckles
usually books usually the inequality notation maybe that seems harder to read that what the inequality actually means... when it says: \[\sum_{n=1}^{\infty}a (r)^n \text{ converges when } |r|<1 \\ \text{ the inequality is saying } -1
freckles
  • freckles
exclusive meaning we are not including -1 and 1
freckles
  • freckles
anyways I'm glad it makes more sense now
anonymous
  • anonymous
thank you, so and pauls notes will have the other test im assuming
freckles
  • freckles
i'm pretty sure and i could be mistaken paul's notes has everything you will need for calculus
anonymous
  • anonymous
again thank you
freckles
  • freckles
np

Looking for something else?

Not the answer you are looking for? Search for more explanations.