anonymous
  • anonymous
Which is the solution set of the equuation a^2-25=0 A:0,-5 B:0,5 C:-5,5 D:-5,-5
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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DanJS
  • DanJS
That is a parabola f(x) = a^2 - 25 Setting that to zero f(x) = 0, will give you when y=0, or the x-axis intercepts
DanJS
  • DanJS
since the squared term is +, the thing will open upwards... When a=0, f(a) = -25, that is the y-intercept and the vertex..
DanJS
  • DanJS
|dw:1447184933114:dw| The solution set includes those two points when y=0, where it crosses the 'a' axis

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anonymous
  • anonymous
I dont get it.
DanJS
  • DanJS
you can solve that with algebra, move the 25 over, square root both sides...
DanJS
  • DanJS
recall, \[\sqrt{x^2}= \left| x \right| \]
DanJS
  • DanJS
ill show you for this one.. \[a^2 - 25 = 0\] a^2 = 25 \[\sqrt{a^2}=\sqrt{25}\] \[ \left| a \right| = 5\]
DanJS
  • DanJS
so a can be +5 or -5
anonymous
  • anonymous
That the answer?
DanJS
  • DanJS
yes, when it asks for the 'solution set'... You just have to find the values for a here. Solving a^2-25=0 for a
anonymous
  • anonymous
I see
DanJS
  • DanJS
and graphing the thing is a good check... https://www.desmos.com/calculator crosses a axis (y=0) when a is +5 and -5 (use x instead of a to graph it
DanJS
  • DanJS
y=x^2-25
anonymous
  • anonymous
Isee. thanks

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