anonymous
  • anonymous
For f(x) = 0.01(2)x, find the average rate of change from x = 3 to x = 8.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@jojo12g
anonymous
  • anonymous
@King.Void.
anonymous
  • anonymous
@MrCoolGuy

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More answers

Vocaloid
  • Vocaloid
rate of change = [f(8)-f(5)]/(8-5)
Ms-Brains
  • Ms-Brains
Can you please snip the whole problem, and paste the link. So I can see the original and help better
anonymous
  • anonymous
1 Attachment
jojo12g
  • jojo12g
@AlexandervonHumboldt2
anonymous
  • anonymous
@Owlcoffee
anonymous
  • anonymous
@Preetha
jojo12g
  • jojo12g
A because 0.01(2)4=0.08 @madison_taylor914
Ms-Brains
  • Ms-Brains
I'm not sure about this one... Sorry Madison.
anonymous
  • anonymous
Which of the following options results in a graph that shows exponential decay? f(x) = 0.6(2)^x f(x) = 3(0.7)^x f(x) = 0.4(1.6)^x f(x) = 20(3)^x
anonymous
  • anonymous
@Ms-Brains
jojo12g
  • jojo12g
A because 0.01(2)4=0.08 @madison_taylor914
anonymous
  • anonymous
thats not what its asking @jojo12g
MrCoolGuy
  • MrCoolGuy
im not sure on this one
misty1212
  • misty1212
HI!!
misty1212
  • misty1212
\[f(x)=0.1\times 2^x\] right?
anonymous
  • anonymous
yes
misty1212
  • misty1212
you need to compute \[f(8),f(3)\] and then take the slope \[\frac{f(8)-f(3)}{8-3}\]
misty1212
  • misty1212
the function is \[f(x)=0.01\times 2^x\] so \[f(8)=2.56\]
misty1212
  • misty1212
\[f(3)=0.01\times 2^3=0.01\times 8=0.08\]
anonymous
  • anonymous
so 2.48 final answer?
misty1212
  • misty1212
no you still have to divide by 5
anonymous
  • anonymous
.496
lochana
  • lochana
yes. that's the answer
anonymous
  • anonymous
thanks guys
misty1212
  • misty1212
\[\color\magenta\heartsuit\]
anonymous
  • anonymous
can you help me with one more? @misty1212

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