anonymous
  • anonymous
Describe the graph of the function f(x) = x3 − 18x2 + 107x − 210
Algebra
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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DanJS
  • DanJS
what info do you usually need... this is a cubic equation, polynomial
DanJS
  • DanJS
remember the look of y=x^3 |dw:1447192941666:dw|
anonymous
  • anonymous
Describe the graph of the function f(x) = x3 − 18x2 + 107x − 210. Include the y-intercept, x-intercepts, and the shape of the grap

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anonymous
  • anonymous
Thats what I need
DanJS
  • DanJS
that is the general shape, the squared term will mess with that middle section a bit Graph the general form here y = A*x^3 + B*x^2+C*x+D Select 'add sliders' for ABCD, mess with those coefficient values and watch the graph
DanJS
  • DanJS
https://www.desmos.com/calculator
DanJS
  • DanJS
well the y intercept is when x=0, just solve that point
anonymous
  • anonymous
I just dont know how to describe it, nor the shape
DanJS
  • DanJS
Maybe start by saying, the general shape is similar to that of y=x^3 did you make that graph with sliders on the other page?
DanJS
  • DanJS
notice if A is + vs A is -, the way the ends of the graph look
anonymous
  • anonymous
Yeah made the graph on the page you sent me
DanJS
  • DanJS
You can show that a cubic has at least one real root (x-intercept), because if you take very large values for x, the cube term dominates, and the ends of the graph for x is large + and -, go off to huge values for f(x) in opposite directions... the range is then all real numbers, and it must cross the x axis somewhere at least once then, to go from -huge number to a + huge number, the sign must change
DanJS
  • DanJS
Go to that site, in the place where you put things in on the left.. put a*x^3+b*x^2+c*x+d hit to add sliders for all 4, a,b,c, and d play with the values and watch the effects
anonymous
  • anonymous
Okay Thanks love
DanJS
  • DanJS
you can see how each term affects the graph, for yorus f(x) = x3 − 18x2 + 107x − 210 a=1 b=-18 c=107 d=-210 probably have to zoom way out and set the scale on the axis to see it good
DanJS
  • DanJS
just describe what it looks like and why
DanJS
  • DanJS
For huge x values, the function f(x) goes off to +infinity because the coefficient on the x^3 term 'A' is positive...
DanJS
  • DanJS
to get the x intercepts, (must be at least one real value), solve for f(x) =0 if it is a book problem, that probably factors nicely so you can get nice values for x
DanJS
  • DanJS
f(x) = x3 − 18x2 + 107x − 210 = ( )*( )* ( ) = 0 ( )*( )* ( ) = 0 you can tell from the graph with those values for B and C and D, it will have 3 x-intercepts, so it may factor into that form
anonymous
  • anonymous
for those x - intercept wouldnt it be (5,0) (6,0) (7,0)
anonymous
  • anonymous
@DanJS
DanJS
  • DanJS
yes, that factors nice into those 3 quantities
DanJS
  • DanJS
for f(x) =0, x can be 5, or 6 or 7
anonymous
  • anonymous
So for y it would be -210
DanJS
  • DanJS
yes, (0,y) , when x is zero
DanJS
  • DanJS
Maybe explain the end behavior for the graph when you let x be very large possitive and negative... the larger x becomes, the more the x^3 term will completely dominate the value of f(x)
anonymous
  • anonymous
I just dont know how to put all that in an explanation does that make sense
DanJS
  • DanJS
for this one, as x becomes larger and larger, the values of f(x) also become larger and larger without bound, , same for -x, and f(x) going to huge - values
DanJS
  • DanJS
that explains the end behavior of the graph shooting upwards and downwards for ever to infinity
DanJS
  • DanJS
what class is this?
anonymous
  • anonymous
obviously its a math class lol
anonymous
  • anonymous
But for this last assignment I need to explain it but I swear I am horrible at explaining things
anonymous
  • anonymous
So this is so hard for me,
DanJS
  • DanJS
i mena, algebra, pre-calc, calculus ?
DanJS
  • DanJS
If you have to write it out, just go throgh all the posts from me above and should be enough
anonymous
  • anonymous
algebra 2

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