this is my last question. someone help.

- anonymous

this is my last question. someone help.

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- schrodinger

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- anonymous

##### 1 Attachment

- anonymous

Calculate the area of both shapes

- anonymous

Yes, I got that. But I need help on getting there.

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## More answers

- anonymous

Cool. So, do you know how to calculate the area of a rectangle?

- anonymous

P= area of circle/area of rect.?

- anonymous

I think so.

- anonymous

in this problem, would the rectangle be 1.92?

- anonymous

Yep.
So A(rectangle) = base x height
\[and A(circle) = \pi r ^{2}\]

- anonymous

What do I do next?

- anonymous

Yep.
A(rectangle) = (1+1.4) x (0.8) = 1.92

- anonymous

So once you've got the area of the rectangle you need the area of the circle

- anonymous

It would be 0.5 because the radius is 0.4

- anonymous

Yeah
A(circle) = 0.4^2 x 3.1415...

- anonymous

So then, as you said, P= area of circle/area of rect
Simply calculate, using the values that we worked out

- anonymous

How do put that in equation?

- anonymous

P = (0.5) / (1.92)

- anonymous

0.26

- anonymous

.

- anonymous

Exactly

- anonymous

I have these other ones, all I need is someone to check if its right.

- anonymous

answer b

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- anonymous

I agree

- anonymous

answer b.

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- anonymous

@jayzdd is the last question correct?

- anonymous

you got b?

- anonymous

Yes

- anonymous

I'm guessing its wrong?

- anonymous

the circle has area pi * (.8/2)^2

- anonymous

the rectangle has three regions, the left of the circle region of the circle, the circle itself, and the right of the circle region

- anonymous

So what's the equation for it?

- anonymous

lets look at this square here http://prntscr.com/91dlno

- anonymous

it has total area 1.0 * 0.8 = .8
we want to find the probability of falling into
the area outside the semicircle

- anonymous

the semicircle area is 1/2 * pi * (.4)^2
the area to the left of the semicircle is
(1.0)*(.8) - 1/2 * pi * (.4^2)
divide this by total area (1.0)*(0.8)

- anonymous

So calculate (1.0)*(0.8) - 1/2 * pi * (0.4^2) first

- anonymous

we are trying to find the probability of falling into the green area
http://prntscr.com/91do6n

- anonymous

is the square of (0.4^2) meant to be inside or outside?

- anonymous

Do you agree that
green area + blue area = total area

- anonymous

Yes I got that

- anonymous

green area + blue area = total area
plugging in:
green area + 1/2* pi * (.4)^2 = 1.0 * (0.8)
solve for green area
green area = 1.0 * (0.8) - 1/2* pi * (.4)^2

- anonymous

Yes I got 0.54

- anonymous

probability of falling into green
= green area / total area
= .54 / ( 1.0 * 0.8)

- anonymous

actually its better if you keep more decimals
= .54867 / ( 0.8 ) = .6858
this rounds to .69

- anonymous

are we good?

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