anonymous
  • anonymous
this is my last question. someone help.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
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anonymous
  • anonymous
Calculate the area of both shapes
anonymous
  • anonymous
Yes, I got that. But I need help on getting there.

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anonymous
  • anonymous
Cool. So, do you know how to calculate the area of a rectangle?
anonymous
  • anonymous
P= area of circle/area of rect.?
anonymous
  • anonymous
I think so.
anonymous
  • anonymous
in this problem, would the rectangle be 1.92?
anonymous
  • anonymous
Yep. So A(rectangle) = base x height \[and A(circle) = \pi r ^{2}\]
anonymous
  • anonymous
What do I do next?
anonymous
  • anonymous
Yep. A(rectangle) = (1+1.4) x (0.8) = 1.92
anonymous
  • anonymous
So once you've got the area of the rectangle you need the area of the circle
anonymous
  • anonymous
It would be 0.5 because the radius is 0.4
anonymous
  • anonymous
Yeah A(circle) = 0.4^2 x 3.1415...
anonymous
  • anonymous
So then, as you said, P= area of circle/area of rect Simply calculate, using the values that we worked out
anonymous
  • anonymous
How do put that in equation?
anonymous
  • anonymous
P = (0.5) / (1.92)
anonymous
  • anonymous
0.26
anonymous
  • anonymous
.
anonymous
  • anonymous
Exactly
anonymous
  • anonymous
I have these other ones, all I need is someone to check if its right.
anonymous
  • anonymous
answer b
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anonymous
  • anonymous
I agree
anonymous
  • anonymous
answer b.
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anonymous
  • anonymous
@jayzdd is the last question correct?
anonymous
  • anonymous
you got b?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
I'm guessing its wrong?
anonymous
  • anonymous
the circle has area pi * (.8/2)^2
anonymous
  • anonymous
the rectangle has three regions, the left of the circle region of the circle, the circle itself, and the right of the circle region
anonymous
  • anonymous
So what's the equation for it?
anonymous
  • anonymous
lets look at this square here http://prntscr.com/91dlno
anonymous
  • anonymous
it has total area 1.0 * 0.8 = .8 we want to find the probability of falling into the area outside the semicircle
anonymous
  • anonymous
the semicircle area is 1/2 * pi * (.4)^2 the area to the left of the semicircle is (1.0)*(.8) - 1/2 * pi * (.4^2) divide this by total area (1.0)*(0.8)
anonymous
  • anonymous
So calculate (1.0)*(0.8) - 1/2 * pi * (0.4^2) first
anonymous
  • anonymous
we are trying to find the probability of falling into the green area http://prntscr.com/91do6n
anonymous
  • anonymous
is the square of (0.4^2) meant to be inside or outside?
anonymous
  • anonymous
Do you agree that green area + blue area = total area
anonymous
  • anonymous
Yes I got that
anonymous
  • anonymous
green area + blue area = total area plugging in: green area + 1/2* pi * (.4)^2 = 1.0 * (0.8) solve for green area green area = 1.0 * (0.8) - 1/2* pi * (.4)^2
anonymous
  • anonymous
Yes I got 0.54
anonymous
  • anonymous
probability of falling into green = green area / total area = .54 / ( 1.0 * 0.8)
anonymous
  • anonymous
actually its better if you keep more decimals = .54867 / ( 0.8 ) = .6858 this rounds to .69
anonymous
  • anonymous
are we good?

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