Babynini
  • Babynini
Finding where this equals zero o.0 [(x^2+1)(3)-(3x-4)(2x)]/[(x^2+1)^2] = 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Babynini
  • Babynini
So it's not defined when the numerator = 0 correct?
lochana
  • lochana
no. it's not defined when denominator = 0
lochana
  • lochana
you can find solutions by further simplifying

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Babynini
  • Babynini
right, that's what I thought but I got x= -1/3 and 3 which makes the numerator = 0 when simplifying o.0
Babynini
  • Babynini
Simplifying we get: [-(3x+1)(x-3)]/(x^2+1)^2]
lochana
  • lochana
\[\frac{[(x^2+1)3 - (3x-4)2x]}{(x^2 + 1)^2}\] yes. your solutions are correct
lochana
  • lochana
now simply plug each solution in the equation. you will get zero
Babynini
  • Babynini
Right, but I got that by setting the numerator = 0 which is why i'm confused xD
lochana
  • lochana
yes. we normally don't think about denominator when finding solutions to 0. because you can't make the equation zero with denominator.
lochana
  • lochana
so we usually forget denominator and focus on numerator.
lochana
  • lochana
so the idea is that if you make numerator zero. while thing become zero:)
lochana
  • lochana
whole*
lochana
  • lochana
bye
Babynini
  • Babynini
Ah ok. Thanks!

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