joshoyen
  • joshoyen
Solve by isolating the x^2 term and taking the square roots ( + and - ). 1. x^2 = 25 2. x^2 - 16 = 0 3. -2x^2 + 40 = 0
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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DanJS
  • DanJS
recall \[\sqrt{x^2}=\left| x \right|\]
joshoyen
  • joshoyen
oh so you just find the square root of 25
joshoyen
  • joshoyen
?

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More answers

joshoyen
  • joshoyen
how about x^2 - 16 = 0, do you add 16 to both sides?
DanJS
  • DanJS
yes, square root both sides of the =, and remember the abs value
DanJS
  • DanJS
abs value of x = 5, so x can be + or - 5
joshoyen
  • joshoyen
oh so its x = |5|
DanJS
  • DanJS
same for the second, isolate the x^2, take the square root of everything
joshoyen
  • joshoyen
square root of 16 is 4
DanJS
  • DanJS
yes, and the square root of x^2 = absolute value of x because x^2 will be the same for the + or - value of x
joshoyen
  • joshoyen
ahh i see alright thanks!, now how abbout the 3rd one? what step do i do first
DanJS
  • DanJS
\[\sqrt{x^2}=\sqrt{16}\] \[\left| x \right|=4\] x=+ 4 or x=-4
joshoyen
  • joshoyen
gotcha
DanJS
  • DanJS
try the last one
joshoyen
  • joshoyen
is it x^2 - 20 = 0
DanJS
  • DanJS
ok, so you divided everything by -2
joshoyen
  • joshoyen
yep
DanJS
  • DanJS
k, same as #2 prob now
joshoyen
  • joshoyen
ohh okay i see now thanks!
DanJS
  • DanJS
you can do whatever operation you want, as long as it is to both sides of the equation
joshoyen
  • joshoyen
alright gotcha tyvm
DanJS
  • DanJS
i just think move the 40 over by subtracting 40 isolate x^2 by dividing everything by -2 square root everything
DanJS
  • DanJS
welcome

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