anonymous
  • anonymous
Can someone help im terrible at slope pleaseeeeee its urgent
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
anonymous
  • anonymous
i need this done tonight or ill fail the class :((((
lochana
  • lochana
what is hardest part for you?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
all of it , i dont get anything about slope it confuses me and im nervous i wont get it done tonight
lochana
  • lochana
mm.. okay. let's do first part
anonymous
  • anonymous
okay?
lochana
  • lochana
now we don't know what the red line is . So let's assume that y= ax + c now this is our red line
anonymous
  • anonymous
ok
lochana
  • lochana
now look at red line on your graph. it intersects y axis and x axis at -0.5 and 0.5
anonymous
  • anonymous
it looks like it lands on 4?
lochana
  • lochana
do explain:)
anonymous
  • anonymous
it looks like 0.5, 4 where the line meets
lochana
  • lochana
|dw:1447218270161:dw| okay?
lochana
  • lochana
well it should be -1. not -0.5
lochana
  • lochana
i said wrong before
anonymous
  • anonymous
oh okay i get now ! whats the next step
lochana
  • lochana
okay now have two points. (0,-1) and (0.5,0) you can plug each point in our red line equation and find "a" and "c"
lochana
  • lochana
can you give me values for a and c
anonymous
  • anonymous
y=(0,-1)x+(0.5,0)
lochana
  • lochana
Noooooooo
lochana
  • lochana
let me do that
lochana
  • lochana
y = ax + c take our first point (0,-1) now put the values -1 = a*0 + c
lochana
  • lochana
c = -1
anonymous
  • anonymous
um ookay ??
lochana
  • lochana
okay do the same for next point (0.5,0)
lochana
  • lochana
and give the answer for "a" :)
anonymous
  • anonymous
0.5
lochana
  • lochana
since we know c = -1, we don't need to carry c. y= ax - 1 0 = a*0.5 -1 a*0.5 = 1 a = 2
anonymous
  • anonymous
so far is -1=2*0.5-1
lochana
  • lochana
"-1" = 2*0.5 -1 here "-1" is wrong. y value of (0.5,0) is 0. not -1
anonymous
  • anonymous
so then what is Y
lochana
  • lochana
y = 0
anonymous
  • anonymous
so 0=2*0.5-1
lochana
  • lochana
yes
anonymous
  • anonymous
okay how do we solve
lochana
  • lochana
and you get a = 2
lochana
  • lochana
"so 0=2*0.5-1" here you still don't know what the a is. so don't add 2 there. correct one is 0 = a*0.5 -1
anonymous
  • anonymous
ooh alright
lochana
  • lochana
now we know a = 2 and c = -1
lochana
  • lochana
red line is y = ax +c so put answers to the equation y = 2x - 1
lochana
  • lochana
this is the answer for 1st one

Looking for something else?

Not the answer you are looking for? Search for more explanations.