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I think it's A am I correct?
Yea its A
Can you help with 3 more?
solve for y
equation for direct variation is `y=kx` equation for inverse variation is `y=k/x` where k is constant of variation
suppose y varies directly with x, and y=24 when x=8 what is the value of y when x=10? A.10 B.30 C.80 D.240 (I think C am I correct?) @Nnesha @ransondyara471 @yeval76
what did you get for first one ?
nd no direct variation y =kx plugin x =8 y=24 and then solve for k(constant of variation )
@Nnesha can you teach/show me how to get the answer ik you already did but I still don't understand how to solve to get the answer can you do it in steps please
for first one can you solve for y ?
how would you cancel out -4 from left side \[\large\rm -4y=8x\]?
no we don't need to add
it's -4 times y so to cancel out -4 do opposite of multiplication
opposite of multiplication is ??
right divide both sides by -4
so for the first one the correct answer is -2? and not -4?....
can you help me with the second one @Nnesha
what's the equation for `direct variation` ?
correct replace x and y for their values then solve for k
`y=24 when x=8 ` y=kx
so i'd divide 24 by??? k, but what is k. how do I find it? @Nnesha
first replace y with 24 and x with 8 to solve for k would you move 8 to the left side or 24 to the right side ?
8 to the right? 24/8=3 24/24=1
wayes 3 is the constant of variation
what do you mean by 24/24
\[\rm 24=8k\] divide both side by 8 you get k=3 now substitute k for 3 and x for 10 solve for y
I'm confuse. So itll be B. 30 for the answer
yes correct \[\rm y=kx\] k=3 so when x=10 y=? we should replace x with 10 and k with 3 then multiply
thank you. I had no idea how to solve problems like these I somewhat just learned how to do it a little. I'm not a pro but I some what know a little bit of what to do
yeah practice will help you to learn it:=))