The following formula accurately models the relationship between the size of a certain type of a tumor and the amount of time that it has been growing:
where t is in months and V(t) is measured in cubic centimeters. Calculate the rate of change of tumor volume at 100 months.
Stacey Warren - Expert brainly.com
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So you need to find V'(t) then substitute t = 100
correct. Substituting 100 for t results in an exponent of -.24
The answer is 0.103 cm^3
but I don't know how to arrive at that answer.
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That's close but not quite right. I'm just checking to see if my method agrees with your answer
Your answer is in cubic centimeters but the question asks for the rate of change?
The answer is 0.103 cm^3/ month
OK, still checking
Yes, that answer is correct! Now for my solution.
. . . and your solution is ? . . .
the equation editor isn't working
V'(t) =(72/25)e^(-9t/1250)(e^(3t/1250) -1)^2
Substituting t=100 => V'(100) = 0.103
What do the numbers V'(t) =(72/25)e^(-9t/1250)(e^(3t/1250) -1)^2
have to do with the equation V(t)=400(1-e^ -.0024t)^3
V'(t) is the rate of change of V(t) which is the derivative
That is an obvious statement, which does nothing towards helping to answer the question to which you and I have been engaged with over the last hour.
You have provided no help in one hours time. If you do not know how to solve the question, why would you pretend and waist anyone's time?
No you're mistaken, I'm not wasting your time.
Here is the solution to the derivative step by step but I used the variable x instead of t. Had to use my word equation editor