clamin
  • clamin
PLEASE HELP!! MEDAL!! The standard deviations for the blue and yellow teams are shown below. Complete the chart by calculating the variance, (insert equation 1) , and the standard deviation, (insert equation 2), for the red team.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
clamin
  • clamin
|dw:1447265661983:dw|
anonymous
  • anonymous
so what r u exactly doing
clamin
  • clamin
Red team: 47.5, 42, 48.5, 44.5, 47, 41, 48, 43, 49 Yellow team: 47.5, 45.5, 48.5, 46.5, 47, 45, 48, 46, 49 Blue team: 48.1, 46.8, 52, 47.9, 48, 46, 50, 47, 53

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clamin
  • clamin
@lucario1002 I have to solve for the red team using the equation 2. I have to complete the chart
anonymous
  • anonymous
ok now i see
anonymous
  • anonymous
give me a minute
anonymous
  • anonymous
it would be 1.82
anonymous
  • anonymous
@lucario1002 please do not give direct answers...... they need to know how...... thats against the code of conduct
clamin
  • clamin
how did you get 1.82?? @lucario1002
kropot72
  • kropot72
The sample variance of a sample of size n is given by: \[\large s^{2}=\frac{1}{n-1}\sum_{i=1}^{n}(x _{i}-\bar{x})^{2}\] For the red team, x-bar the sample mean is found by adding the data values and dividing by 9. The result is: \[\large \bar{x}=45.61\] The first term in the summation is therefore given by: \[\large (47.5-45.61)^{2}=3.572\] Now you need to find the remaining eight terms in the summation.
kropot72
  • kropot72
@clamin Are you there?
kropot72
  • kropot72
The second term in the summation is found from: \[\large (42-45.61)^{2}=13.032\]

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