iwanttogotostanford
  • iwanttogotostanford
IMMEDIATE H
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Maddy1251
  • Maddy1251
Do you have a picture to explain this function? I do not quite understand it.
anonymous
  • anonymous
the quantity 3y minus 2x all over the quantity 3y plus 2x
iwanttogotostanford
  • iwanttogotostanford
@Maddy1251

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Maddy1251
  • Maddy1251
:)
Maddy1251
  • Maddy1251
|dw:1447267809357:dw|
iwanttogotostanford
  • iwanttogotostanford
yes
Maddy1251
  • Maddy1251
Okay dokay. One minute.
iwanttogotostanford
  • iwanttogotostanford
ok!:-)
Maddy1251
  • Maddy1251
It's been forever since I have done this so forgive me if I am rustry on this concept
iwanttogotostanford
  • iwanttogotostanford
its ok hah! do you want the answer choices??
Maddy1251
  • Maddy1251
One thing about always dealing with fractions is having like denominators, which in this case we have the like denominator of '2' . If you want to post them, you may.
iwanttogotostanford
  • iwanttogotostanford
A. the quantity of x squared plus 11x plus 30, all over 2 B. the quantity of 2x plus 11, all over 2
iwanttogotostanford
  • iwanttogotostanford
ok
Maddy1251
  • Maddy1251
Okay. :D I think I remember how to do these
Maddy1251
  • Maddy1251
They're already in LCM form, so that's a relief. Step one is done
Maddy1251
  • Maddy1251
We want to combine the like terms to each other
Maddy1251
  • Maddy1251
So, we know our denominator will be 2.
Maddy1251
  • Maddy1251
we will work with the top part.
Maddy1251
  • Maddy1251
|dw:1447268558861:dw|
Maddy1251
  • Maddy1251
I want those 'x' variables to have a numerical value to them, makes things much more simple.
Maddy1251
  • Maddy1251
|dw:1447268602037:dw|
Maddy1251
  • Maddy1251
Note ; only 'x' = 1x. Because the '1' in considered 'invisible.
Maddy1251
  • Maddy1251
|dw:1447268644623:dw| This should be the final answer, if I remember correctly. Because we are not dividing or multiplying these terms to each other.
iwanttogotostanford
  • iwanttogotostanford
oh ok- thank you!
Maddy1251
  • Maddy1251
You're welcome, good luck :)

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