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maximum magnitude a static friction force between the box and truck bed can have is f(max)=mui*normal normal is basically mg But you also have to use newtons laws on this problem. F=ma ^ in this case you set the force equal to the frictional maximum force. So thats then mui(mg)=ma If you solve for acceleration, the masses cancel out. So you have left: a=mui*g
in this case your mui due to static friction is 0.51
I hope this helped.
Okay so (.51N)(9.81*351)
No the mass gets canceled out because of the newtons formula.
Okay so just (.51N * 9.81)?
thats not a N, thats mui.
http://www.mrwaynesclass.com/ap/Ch4_freebody/CH04W59.pdf. Look at how this page derives the equation.
So you wouldn't find acceleration by multiplying the gravity by mui?
Wheres the error404 coming from :)
It did that when I clicked on it.
http://www.mrwaynesclass.com/ap/Ch4_freebody/CH04W59.pdf I think the extra spaced messed up the link.
just copy and paste the link withouth the extra spaces.
For this would I just take (.51)(9.81)=5.0031
Always start with: |dw:1447296703167:dw| From there, you know that Force of gravity is equal to the normal force, since the object will only move horizontally. So the y-components of force will be equal to zero: Fnormal - Fgravity = 0 N -->eqn 1 To solve for the Friction Force which is required to solve for the maximum acceleration, you need the formula for the normal force. From the eqn 1, rearrange it in terms of Fnormal: Fnormal = Fgravity Fnormal = mass x acceleration due to gravity (SO CALCULATE THIS FIRST- just leave the mass as variable "m" for now) The formula for the Friction force is: |dw:1447297058064:dw| where Fn is the normal force, µ is the coefficient of friction Subsitute the values and solve for Ff. NEXT SOLVE FOR ACCELERATION: According to Newton's second law, the object must move on the direction of the friction force, since it is the only force remaining that will cause the object to move: Ff = mass x acceleration rearrange the formula and you'll get : acceleration = force / mass variable 'm' should cancel out.
that is for letter A.
For letter B, you have to refer to your solution on letter A. Since you cancel the 'm' or the mass on your calculation, do you think having different mass matters to have a safe acceleration?
So from letter A, what normal force did you get?
Fgrav= (9.81)(351) = 3443.31 =Fnorm
right, now solve for the friction force using that normal force and the coefficient of friction, what will you get?
So would the m be .51?
it is µ= 0.51, not the m. just ignore the 'm' for now--we'll use it on letter B.
So Ff = mui 3443.31
yeah but mui is 0.51 , so you can solve for Ff: 0.51 x 3443.31
Alright I was thinking that. I got Ff=1756.0881
okay good :D now solve for acceleration
I divide the 1756 by the mass right
..and you'll get?
yes :) that will be your acceleration, don't forget your unit :)
Right. 5.00 m/s^2
yes, perfect. For B, instead of substituting the values, use variables instead to solve for 'a' ... and go back the question I asked about letter B.
I don't really see why the mass of the truck would matter.
yes, your answer is kinda right, but you have to know the reason why the mass of the loads would not matter :)
So it because the mass would just cancel out
yeah , that's how I will reason it :P
Thanks for the help
np :) goodluck with the rest of your physics