anonymous
  • anonymous
What is (x^2 - 2xy + y^2) + (x^2 - 2xy + y^2)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
help or answer?
anonymous
  • anonymous
I think it might be \[x^2 + y^2\]
anonymous
  • anonymous
Well I'm pretty sure I know the answer but I wanna know if i did it right @themazinmathmaster

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anonymous
  • anonymous
I'm just confused about exponent rules. When you add \[x^2 + x^2\] it equals \[x^2\] right? Or is it 2x^2 ?
anonymous
  • anonymous
@Preetha @thomaster
johnweldon1993
  • johnweldon1993
Nope just 2x^2 *in that example*
anonymous
  • anonymous
ok wait so
anonymous
  • anonymous
so wait can you help me with the equation?
anonymous
  • anonymous
this is what I did \[(x^2 - 2xy + y^2) + (x^2 - 2xy + y^2)\]
johnweldon1993
  • johnweldon1993
Sure :) \[\large (x^2 - 2xy + y^2) + (x^2 - 2xy + y^2)\] We dont need these parenthesis \[\large x^2 - 2xy + y^2 + x^2 - 2xy + y^2\]
johnweldon1993
  • johnweldon1993
Oh okay yeah, show me what you did :)
anonymous
  • anonymous
ok so the 2xy's cancel out ofc
anonymous
  • anonymous
but then the x^2 + x^2 and the y^2 + y^2
anonymous
  • anonymous
what do you do with those? are they turned into 2x^2 + 2y^2 like you said?
johnweldon1993
  • johnweldon1993
Are you sure about that? Lets rearrange that whole equation \[\large x^2 + x^2 - 2xy - 2xy + y^2 + y^2\] What is -2xy - 2xy?
anonymous
  • anonymous
OHHH hahaha omg ok so it's -4xy right?
anonymous
  • anonymous
or do you have to add the exponents there too?
johnweldon1993
  • johnweldon1993
Lol no you had it right the first time :) Remember, when we are adding...we never touch the exponents...just the base example: \[\large 1x^2 + 1x^2 = 2x^2\] never touched the x^2 part
anonymous
  • anonymous
ok so instead I shoud've down x^2 + x^2 = 2x^2
anonymous
  • anonymous
*done
johnweldon1993
  • johnweldon1993
Correct \[\large x^2 + x^2 - 2xy - 2xy + y^2 + y^2\] \[\large 2x^2 - 4xy + 2y^2\] right? :)
anonymous
  • anonymous
ya ok that makes sense. Sorry this was such a lame question, I'm a little rusty lol. Anyway thank you so much!! Really appreciate it
johnweldon1993
  • johnweldon1993
Lol no problem, we all have days :P

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