MEDALS!
What is the product of five square root five times six square root four? Simplify your answer.
thirty square root nine
Sixty square root five
Sixty square root twenty four
one hundred fifty square root four

- anonymous

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- anonymous

Help :-:

- DanJS

\[5*\sqrt{5}*6*\sqrt{4}\]
= ..

- xkshx

|dw:1447290171305:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- xkshx

sorry took so long

- DanJS

this one is kinda simple, you can take the root of 4, then multiply everything together, that is all

- anonymous

so 132 for the first step.

- DanJS

or the way usually if you cant simplify off the bat...
\[a \sqrt{b} * c \sqrt{d} = (a*c)\sqrt{b*d}\]
properties of powers or roots

- anonymous

It should be the second one.

- xkshx

\[60\sqrt{5}\]

- DanJS

it is a string of 4 things multiplied together, 2 roots and 2 numbers

- anonymous

132 is the whole number I used without the decimal.

- anonymous

Thank you guys

- anonymous

You both helper but...

- anonymous

There's only one medal I could give.

- anonymous

I will Medal one of you and fan another, sound fine?

- DanJS

what is the 132 you put?

- anonymous

132.(random numbers)

- anonymous

It was 134 but I took the decimals from both sides out to make life easy.

- DanJS

i'm not sure what you did

- anonymous

Mmm want me to show you?

- DanJS

oh a decimal approximation for the thing.. haha ok

- anonymous

Can you help me with one more please?

- DanJS

sure go for it

- anonymous

Thanks.

- anonymous

The side of a square is Three raised to the five halves power inches. Using the area formula A = s2, determine the area of the square.
A = 9 square inches
A = 15 square inches
A = 225 square inches
A = 243 square inches

- DanJS

these probs all use the properties of exponents... there are like 4 or 5 maybe that you have to remember, just the pattern for manipulating things..

- DanJS

so you want to square 3^(5/2)

- anonymous

15.625?

- DanJS

the property you have to remember is
\[\large b^a * b^c = b^{a+c}\]
when multiplying like bases raised to exponents, you add the exponents like that

- DanJS

so what would happen if you multiplied 3^(5/2) * 3^(5/2)

- DanJS

the bases have to be the same to combine them, both 3 here

- anonymous

6^(10/2)?

- DanJS

Or you can remember to just square the thing, by using another property for exponents
a power raised to anothe rpower, you multiply them together to simplify like that
\[\large [b^a]^c = b^{a*c}\]

- DanJS

close, you added the powers right, the base doesnt change though

- anonymous

Oh the base was 5?

- anonymous

Mmm?

- DanJS

For example if you have 2^2 * 2^5, you get a total of 7 2's if you expand those powers out 2*2*2*2*2*2*2, so the powers add , the base is the same

- DanJS

no, you have to square th elength of the side or multiply 2 of them together
3^(5/2) * 3^(5/2)
=
3^(10/2)

- DanJS

if you square it ,
[3^(5/2)] ^2 = 3^(10/2) same

- DanJS

then just simplify the 10/2 to a 5, and raise 3 to the 5th power for the answer

- DanJS

after a couple practice probs, you will remember the patterns for combining powers, not to bad

- anonymous

243

- anonymous

That would be D

- DanJS

3*3*3*3*3

- DanJS

yea

- anonymous

Thank you very much!

- anonymous

With your methods, I think I could manage a problem like this.

- DanJS

welcome,
these are the things to practice till you dont have to think about it
http://image.slidesharecdn.com/7-2propertiesofrationalexponents-130128131758-phpapp02/95/72-properties-of-rational-exponents-2-638.jpg?cb=1359379179

- DanJS

and something to zero power is 1
roots are fraction powers
square root(b) = b^(1/2)

- DanJS

thats about it prolly, goodluck

- anonymous

Thanks

Looking for something else?

Not the answer you are looking for? Search for more explanations.