briana.img
  • briana.img
Need help on word problem.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
briana.img
  • briana.img
This is the word problem and what I have is what I have on there so far I'm stuck
1 Attachment
anonymous
  • anonymous
your trying to solve for t so you need to get t on its own side of the equation by itself.
anonymous
  • anonymous
h = Vo*t + 0.5g*t^2 Vo = 192 Ft/s g = -32Ft/s^2 h = 432 Ft. Solve for t(Use Quadratic formula). h max = -(Vo^2)/2g = -(192^2)/-64 = 576 Ft. what math class are you in?

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anonymous
  • anonymous
@briana.img
briana.img
  • briana.img
sorry i was called but i'm taking algebra 2
anonymous
  • anonymous
im in algebra 2 also. i actually did this problem a couple of weeks ago and that was the answer.
briana.img
  • briana.img
@kourtney2014 where'd you get 0.5 from?
briana.img
  • briana.img
it doesn't look like the same problem??
anonymous
  • anonymous
ill explain
briana.img
  • briana.img
i'm really confused lol
briana.img
  • briana.img
@johnweldon1993 can you please help?
johnweldon1993
  • johnweldon1993
I was gonna let @kourtney2014 explain first :)
briana.img
  • briana.img
@johnweldon1993 she seems to have left??
johnweldon1993
  • johnweldon1993
Okay :) so we have \[\large h = 192t - 16t^2\] we want to know t when h = 432 \[\large 432 = 192t - 16t^2\] If you look, everything is divisible by 16...so we can bring these numbers smaller a bit Divide everything by 16 \[\large 27 = 12t - t^2\] Looks better to me Now we solve for ;t;...we can use the quadratic formula for that \[\large -t^2 + 12t - 27 = 0\] \[\large \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] This will solve for 't'
briana.img
  • briana.img
ooooh okay!! thank you!!! didn't know you could take apart 16 from the t^2
johnweldon1993
  • johnweldon1993
Hey! that got deleted for some reason?? :O grr gotta type it out again! lol
briana.img
  • briana.img
no it didn't get deleted?
johnweldon1993
  • johnweldon1993
The part b) part? You still see it?
briana.img
  • briana.img
@johnweldon1993 ooooh no i never saw it sorry about that but i got 3 and 9 for the answers for the quadratic formula
briana.img
  • briana.img
i'll plug them in and see which one is correct?
briana.img
  • briana.img
wait nevermind they both work when i plug them back into the original equation lol
johnweldon1993
  • johnweldon1993
They both will be :) What does that mean though?? :O
johnweldon1993
  • johnweldon1993
Hint* Think about the path this is traveling :) |dw:1447295459962:dw| As it is going up...at t = 3...it will hit 432 feet and then again at 9...as it is falling back down...it will hit it again!
briana.img
  • briana.img
Well I know after 3 seconds it hits the heigh of 432 but what is the maximum height that the rocket reaches??
briana.img
  • briana.img
9 has to do with that?
johnweldon1993
  • johnweldon1993
Lol okay good part 1 done...yes t = 3 Now!!!!!! part b) forget everything we've done lol
briana.img
  • briana.img
But doesn't it have to do with what we've done? The maximum point on that graph you made would be the answer?
johnweldon1993
  • johnweldon1993
No jk haha...remember the equation \[\large -t^2 + 12t - 27 = 0\]
briana.img
  • briana.img
We have to substitute 9?
johnweldon1993
  • johnweldon1993
And yes, the maximum point would be the answer...but what would that be? Lets look at that little graph I did |dw:1447295797313:dw| Kinda makes sense that it would be halfway between 3 and 9 in terms of time right?
briana.img
  • briana.img
Yeah!! (((sorry it takes me a while to reply open study is so glitchy i have to refresh every time i wanna reply)))
johnweldon1993
  • johnweldon1993
I know same here lol So that would be at time = 6 right? What would your equation *original equation* come out to at t= 6??
briana.img
  • briana.img
I get 9!!
johnweldon1993
  • johnweldon1993
Work with that original equation \[\large h=192t−16t^2\] plug in t = here :)
johnweldon1993
  • johnweldon1993
Remember everything we have done has been from this beginning equation To find out t at 432...we just made h = 432 Now we want to KNOW 'h' now what we know at t = 6 is the max height...so from that...just plug in 6 for 't' and solve for 'h'
briana.img
  • briana.img
576!!
johnweldon1993
  • johnweldon1993
BAM!!! you got it :D
briana.img
  • briana.img
@johnweldon1993 hey thanks for helping me!!! really appreciate it!! have a good night!!
johnweldon1993
  • johnweldon1993
Of course :) You as well!

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