Last question of the night will probably be a really quick question just need some reassurance.
Two students, Ann and Max, factored the trinomial 4x^2 − 6x − 4. Ann factored it as 2(x − 2)(2x + 1) and Max factored it as (x − 2)(4x + 2). Indicate which student factored the trinomial completely and which student did not, and explain why.
Stacey Warren - Expert brainly.com
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@Vocaloid i believe Ann factored it completely but im not completely sure
this is what i got so far from working it out
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4x^2 − 6x − 4 =
2 ( 2x^2 -4x+1x-2) = you want two numbers that multipy to -4 and add to -4
so -2*2=-4 and -2+-2 = -4
2 ( 2x^2 -4x+1x - 2) =
2 [ 2x (x -2) + 1* (x - 2)] = (x -2 is a common factor
2 * (x - 2) (2 x + 1)
ok so max left out the 2 right
Ann factored it as 2(x − 2)(2x + 1) and Max factored it as (x − 2)(4x + 2).
Ann factored it correctly and completely.
Max's factoring is correct but is not complete because as you said, he could have factored out another 2.
oh ok thank you so very much @Directrix it makes a lot more sense now :D