Curry
  • Curry
Having trouble figuring out how to remove duplicate counts in probability.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Curry
  • Curry
2. There are 3 possible configurations to have 6 consecutive ones in a binary string of length 8. 1st Option – 6 ones from position 1 to 6. 2nd Option – 6 ones from position 2 to 7. 3rd Option – 6 ones from position 3 to 8. However, need to exclude duplicate cases.
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Curry
  • Curry
@dan815
dan815
  • dan815
okay

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dan815
  • dan815
when its all 1s it exists in all 3 when its 1s from 1 to 7 it exists in first 2 when its 1s fro 2 to 8 it exists in last 2
dan815
  • dan815
2^8 - 6
Curry
  • Curry
Is there a methodical way to think about this? or do i need to always jsut consider different cases?
dan815
  • dan815
umm i dunno i just thouht about it like this
dan815
  • dan815
so u can have all 1s there is 1 for this 7 of 1s-- there are 2 for this 6 of 1s -- there are 3 arrangements for htis 1+2+3=6
dan815
  • dan815
oh wait there are more umm
Curry
  • Curry
kk, that makes sense. Thank you!
dan815
  • dan815
no theres more to it than just that let me think
dan815
  • dan815
the 8 of 1s 7 of 1s case is fine
dan815
  • dan815
now for the 6 of 1s
dan815
  • dan815
there are actually 5 cases
dan815
  • dan815
|dw:1447304204942:dw|
dan815
  • dan815
|dw:1447304261872:dw|
dan815
  • dan815
thus u have 8 of 1s = 1 way 7 of 1s = 2 ways 6 of 1s = 5 ways 2^8-(1+2+5) = total ways with no 6 consecutive 1s
Curry
  • Curry
gotchya gotchya! thnk you!

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