readergirl12
  • readergirl12
The length of a rectangle is 8 in. more than its width. The perimeter is 52 in. What is the length of the rectangle? ? in.
Mathematics
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SOLVED
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chestercat
  • chestercat
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dayakar
  • dayakar
let width =x in length = width+ 8 = x+8
dayakar
  • dayakar
do u know perimeter formula
readergirl12
  • readergirl12
Um.. l+w?

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More answers

dayakar
  • dayakar
no 2(l+w)=p
dayakar
  • dayakar
substitute above values in the equation can u do it
dayakar
  • dayakar
2(x+8+x)=52
readergirl12
  • readergirl12
Ugh.. I was doing it in my head.. xD
dayakar
  • dayakar
2(2x+8) =52
readergirl12
  • readergirl12
It is 12..?? o.e
dayakar
  • dayakar
no show your work
readergirl12
  • readergirl12
Oh mer gerd.. This is so DIFFICULT .. >.<
dayakar
  • dayakar
2x+8=52/2
dayakar
  • dayakar
2x+8 =26 find x
readergirl12
  • readergirl12
Okie.. Subtract both sides from 8? |dw:1447336254574:dw|
dayakar
  • dayakar
2x= 18
readergirl12
  • readergirl12
Mkay.. What else do I do?
dayakar
  • dayakar
x= 18/2 x=9
dayakar
  • dayakar
get it
readergirl12
  • readergirl12
Oh wow... THANK YOUUUUU ♥
dayakar
  • dayakar
width =x =9in l= x+8= find it
readergirl12
  • readergirl12
I'm not sure how...
anonymous
  • anonymous
All 4 sides have to add to the perimeter 52, so s1 + s2 + s3 + s4 = (w)+(w+8)+(w)+(w+8) = 4w+16 = 52 So you need to solve 4w + 16 = 52
readergirl12
  • readergirl12
9...
dayakar
  • dayakar
l=x+8 = 9+8 l=17in

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