nuccioreggie
  • nuccioreggie
HELP
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
nuccioreggie
  • nuccioreggie
The figure shows a line graph and two shaded triangles that are similar: A line is shown on a coordinate grid. The x axis values are from negative 20 to positive 20 in increments of 4 for each grid line. The y axis values are from negative 5 to positive 5 in increments of 1 for each grid line. The line passes through the ordered pairs negative 16, negative 4, and 0, 0, and 16, 4. A shaded right triangle is formed so that its hypotenuse is from ordered pair 0, 0 labeled as O to negative 8, negative 2 labeled as A, one leg is from 0, 0 to 0, negative 2, and the second leg is from 0, negative 2 to negative 8, negative 2. Another shaded right triangle is formed with the hypotenuse from negative 8, negative 2 to negative 12, negative 3 labeled as B, one leg is from negative 8, negative 2 to negative 8, negative 3, and the second leg is from negative 12, negative 3 to negative 8, negative 3. Which statement about the slope of the line is true? The slope from point O to point A is fraction 1 over 4 time the slope of the line from point A to point B. The slope from point O to point A is four times the slope of the line from point A to point B It is 4 throughout the line. It is fraction 1 over 4 throughout the line.
nuccioreggie
  • nuccioreggie
@Michele_Laino
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nuccioreggie
  • nuccioreggie
@welshfella

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More answers

anonymous
  • anonymous
omg what grade math is this?
nuccioreggie
  • nuccioreggie
8th
nuccioreggie
  • nuccioreggie
@Michele_Laino
anonymous
  • anonymous
oh 8 that shouldnt be hard for me then wtf
nuccioreggie
  • nuccioreggie
@Michele_Laino please help
Michele_Laino
  • Michele_Laino
hint: slope of segment OA, is: \[\huge - \frac{{0 - {y_A}}}{{0 - {x_A}}} = ...?\]
Michele_Laino
  • Michele_Laino
whereas, slope of AB is: \[\huge \frac{{{y_A} - {y_B}}}{{{x_A} - {x_B}}} = ...?\] going from \(A\) to \(B\)
nuccioreggie
  • nuccioreggie
so the answer is B @Michele_Laino
Michele_Laino
  • Michele_Laino
are you sure?
nuccioreggie
  • nuccioreggie
@yes i think what do you think the answer choice is for this question?
nuccioreggie
  • nuccioreggie
@Michele_Laino
Michele_Laino
  • Michele_Laino
please compute both slopes, using my formulas above, what do you get?
nuccioreggie
  • nuccioreggie
c
Michele_Laino
  • Michele_Laino
I'm sorry, option C. is a wrong option
nuccioreggie
  • nuccioreggie
i ment D sorry
Michele_Laino
  • Michele_Laino
why it is option D.?
nuccioreggie
  • nuccioreggie
i think it is because when you compute or it could be A
nuccioreggie
  • nuccioreggie
?
Michele_Laino
  • Michele_Laino
hint: \[\begin{gathered} - \frac{{0 - {y_A}}}{{0 - {x_A}}} = - \frac{{0 - \left( { - 2} \right)}}{{0 - \left( { - 8} \right)}} = ...? \hfill \\ \hfill \\ - \frac{{{y_A} - {y_B}}}{{{x_A} - {x_B}}} = - \frac{{ - 2 - \left( { - 3} \right)}}{{ - 8 - \left( { - 12} \right)}} = ...? \hfill \\ \end{gathered} \]
nuccioreggie
  • nuccioreggie
oh its A
Michele_Laino
  • Michele_Laino
if you try to compute those quantities above, you will find the same value in both cases, and such value is \(-1/4\), so what can you conclude?
nuccioreggie
  • nuccioreggie
oh so the answer is D
Michele_Laino
  • Michele_Laino
correct! I'm sorry since my formulas have the wrong sign, here are the right formulas: \[\begin{gathered} \frac{{0 - {y_A}}}{{0 - {x_A}}} = \frac{{0 - \left( { - 2} \right)}}{{0 - \left( { - 8} \right)}} = \frac{1}{4} \hfill \\ \hfill \\ \frac{{{y_A} - {y_B}}}{{{x_A} - {x_B}}} = \frac{{ - 2 - \left( { - 3} \right)}}{{ - 8 - \left( { - 12} \right)}} = \frac{1}{4} \hfill \\ \end{gathered} \]
nuccioreggie
  • nuccioreggie
ohhh ok thank you i just need help with a few more i will tag you friend
Michele_Laino
  • Michele_Laino
ok!

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