anonymous
  • anonymous
Confused with a question: At a processing plant, olive oil of density 875 kg/m3 flows in a horizontal section of hose that constricts from a diameter of 2.80 cm to a diameter of 1.50 cm. Assume steady, ideal flow. change in pressure between the two sections of hose is 4.85 kPa.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Its continuous flow so A1V1=A2V2 and P2-P2=(1/2)p(V^2-V^2)
anonymous
  • anonymous
I know the answer, I just can't figure out how to work the solution
anonymous
  • anonymous
and the question is how to find the flow rate

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anonymous
  • anonymous
Wow you're attractive, but anyway... Flow rate is just the change in volume over time right?
anonymous
  • anonymous
yes in m^3/s
anonymous
  • anonymous
You have the two equations, so you can find the change in volume
anonymous
  • anonymous
i try solving for velocity and multiplying it by its corresponding area, but i dont get the right answer. The answer is 0.000614 m^3/s
anonymous
  • anonymous
I dont wanna write it out lol...but i will :p
anonymous
  • anonymous
Gimme a bit
anonymous
  • anonymous
What did you get for your velocity?
anonymous
  • anonymous
hold on, i erased it
anonymous
  • anonymous
i got 0.03 for V1
anonymous
  • anonymous
and .109 for V2
anonymous
  • anonymous
Ew my laptop is legit running out of battery...but basically with the P2-P1=(1/2)p(V2^2-V1^2) you can solve for distance, as this is the same as P2-P1=(1/2)p(A2^2-1^2)*d^2
anonymous
  • anonymous
Once you have distance i think this question is literally the same as this one: https://answers.yahoo.com/question/index?qid=20120422090134AA5B9nS but with different numbers
anonymous
  • anonymous
i miss typed...its (1/2)p(A2^2-A1^2)*d^2
anonymous
  • anonymous
If you still need help just search "water speed in a constricted pipe" most of the questions are the same anyway lol
anonymous
  • anonymous
oh okay thanks a lot!

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