anonymous
  • anonymous
The point (3, -4) is on the terminal side of 0. Evaluate sin 0, cos 0 and tan 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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zepdrix
  • zepdrix
|dw:1447355085179:dw|
anonymous
  • anonymous
Is tan -4/3?
zepdrix
  • zepdrix
Use the information to form a triangle like this. 3 in the positive x direction, 4 in the negative y direction gives us our point. Do you understand how to find the hypotenuse? :)

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zepdrix
  • zepdrix
\(\large\rm \tan\theta=\dfrac{-4}{3}\) Mmm yes good.
anonymous
  • anonymous
No
zepdrix
  • zepdrix
Pythagorean Theorem. \(\large\rm 3^2+(-4)^2=?\)
anonymous
  • anonymous
9+16=25?
zepdrix
  • zepdrix
Oops my bad :) Our Pythagorean Theorem tells us: \(\large\rm a^2+b^2=c^2\) So we've found the `square of` the longest side.\[\large\rm 3^2+(-4)^2=c^2\]\[\large\rm 25=c^2\]
anonymous
  • anonymous
Okay so tan = -4,3 sin = -4/25 and cos = 3/25?
zepdrix
  • zepdrix
Woops, hold on. We found the `square of` the longest side, we didn't find the longest side length yet. How do we undo the squaring?
anonymous
  • anonymous
divide in half?
anonymous
  • anonymous
find square root
anonymous
  • anonymous
5?
zepdrix
  • zepdrix
Hmm Divide will undo Multiplication. Subtraction will undo Addition. Ah Square Root will undo Square! :) Good.
zepdrix
  • zepdrix
|dw:1447355589286:dw|
anonymous
  • anonymous
I got it now thank you
zepdrix
  • zepdrix
When you're labeling your sides, it's easy to forget which ones are supposed to be positive and negative and all that jazz. Something to note: `The Hypotenuse will always be positive`
zepdrix
  • zepdrix
k cool :)

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