TheCalcHater
  • TheCalcHater
Given h(x)=2cos x-sin 2x, according to the First Derivative Test for what values of x does h have a relative minimum on the interval (-pi,pi)? x=-5pi/6 x=-5pi/6,-pi/6 x=-5pi/6,-pi/6,pi/2 x=pi/2 What are the points of inflection of k(x)=sin -1/4 sin 2x? x=-pi/3 x=-pi/6 x=-pi/3,pi/x x=-pi/3,0,pi/3
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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TheCalcHater
  • TheCalcHater
For the second one I know it is either C or D.
jigglypuff314
  • jigglypuff314
@Loser66 @welshfella
welshfella
  • welshfella
First find the derivative of cos x - sin 2x can you do that?

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More answers

welshfella
  • welshfella
sorry i have to go right now but I see Loser66 is here I'm sure he'll be able to help
Loser66
  • Loser66
The first derivative of h(x) is ?? your answer above is not correct
TheCalcHater
  • TheCalcHater
he gave me a different function of h(x) he dropped the 2 from the front f the cos
Loser66
  • Loser66
type it here, please
TheCalcHater
  • TheCalcHater
the derivative of h(x) is -2cos 2x - 2 sin x
Loser66
  • Loser66
I meant the original h(x) =?
TheCalcHater
  • TheCalcHater
2 cos x-sin 2x
TheCalcHater
  • TheCalcHater
Am I correct for the second question with c or d?
Loser66
  • Loser66
solve one by one, please, the first one, h(x) = 2 cos x - sin(2x), sure?
TheCalcHater
  • TheCalcHater
yeah
Loser66
  • Loser66
h'(x) = (2cos(x) )' - (sin(2x))' = -2sin(x) - 2cos (2x) Now, set it =0 and solve for x. What do you get?
TheCalcHater
  • TheCalcHater
I dont understand?
TheCalcHater
  • TheCalcHater
When I plug it into a calculator it says ERROR
Loser66
  • Loser66
no way to solve by calculator, you must solve it by hand
TheCalcHater
  • TheCalcHater
can you walk me through the steps?
TheCalcHater
  • TheCalcHater
I'm sorry I never had pre calc
Loser66
  • Loser66
What?? no precal? how to solve cal problem?
TheCalcHater
  • TheCalcHater
They made me skip it guidance counselor told me a could handle it and i am barely passing
Loser66
  • Loser66
ok
TheCalcHater
  • TheCalcHater
ok so can you walk me through it ?
Loser66
  • Loser66
I don't, but wolfram can help. read it carefully. http://www.wolframalpha.com/input/?i=-2sinx+-+2cos%282x%29+%3D0+
TheCalcHater
  • TheCalcHater
So which is the answer? I am leaning towards C
Loser66
  • Loser66
last one, x =pi/2
TheCalcHater
  • TheCalcHater
ok thank you now to the second one. I think it is c or d I cant figure out whether 0 is included or not
TheCalcHater
  • TheCalcHater
@jim_thompson5910 @pooja195 @TheSmartOne
jim_thompson5910
  • jim_thompson5910
The second one has \[\Large k(x) = \sin(x) - \frac{1}{4}\sin(2x)\] right? or no?

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