anonymous
  • anonymous
Differentiation Question:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
According to Wolfram Alpha the derivative of \[\sin ^x(x)\] is \[\sin ^x(x)(x \cot (x) + \ln (\sin (x)))\] but when I work it out I get \[\ln (\sin (x))+\cot (x)\ln (x)\] Could someone explain if how they're equal, if they are actually equal?
anonymous
  • anonymous
@Hero ? @Preetha ?
anonymous
  • anonymous
they are not equal

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anonymous
  • anonymous
\[\sin^x(x)=e^{x\ln(\sin(x))}\] take the derivative of that using the chain rule and the product rule
anonymous
  • anonymous
is that what you did, or did you "take the log" you get the same answer either way, all the work is taking the derivative of \[x\ln(\sin(x))\]
anonymous
  • anonymous
@satellite73 Ok, thanks, I see my error now.

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